Part 1)
area of triangle=b*h/2
b=2.9 cm
h=9 cm
so
area=2.9*9/2-----> 13.05 cm²
the answer part 1) is 13.05 cm²
Part 2)
area of the figure=area of rectangle+area of triangle
find the area of rectangle
area rectangle=b*h
b=12 ft
h=?
tan 45=1
tan 45=h/(22-10)----------> h/10=1-------> h=10 ft
area of rectangle=12*10-----> 120 ft²
area of triangle=b*h/2
b=10 ft
h=10 ft
area of triangle=10*10/2----> 50 ft²
area of the figure=120+50----> 170 ft²
the answer Part 2) is 170 ft²
Part 3)
<span>the area of kite is half the product of the diagonals.
</span>Area=(d1*d2)/2
d1=5+5---> 10 ft
d2=16+8----> 24 ft
area=(10*24)/2----> 120 ft²
the answer Part 3) is 120 ft²
Part 4)
the area of rhombus is half the product of the diagonals.
Area=(d1*d2)/2
d1=6+6---> 12 m
d2=6+6----> 12 m
area=(12*12)/2----> 72 m²
the answer part 4) is 72 m²
Part 5)
area of the figure=6*area of one triangle
area of triangle=b*h/2
b=4 cm
is an equilateral triangle
applying the Pythagoras theorem
h²=4²-2²-----> h²=12-----> h=2√3 cm
area of triangle=4*2√3/2----> 4√3 cm²
area of hexagon=6*(4√3)----> 24√3 cm²
the answer Part 5) is 24√3 cm²
Answer:
3.50
Step-by-step explanation:
if you divide 18 by 702 you will get 39 and 136.50 divided by 39 is 3.50. and to make sure this is right you can multiply 3.50 by 39 and you will get 136.50
Answer is
y -14= 6x^2 + 18x
1: B
because a triangle angles all have to add up to 180
