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Dmitrij [34]
4 years ago
10

Sam added two fractions together and got 7/8 as the answer. Write down two fractions that Sam could of added.

Mathematics
1 answer:
Talja [164]4 years ago
4 0
3/8 and 4/8
3/8 + 4/8 = 7/8
Or
2/16 + 3/8 = 7/8
Because 2/16 = 4/8
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Kite EFGH is inscribed in a rectangle such that F and H are midpoints and EG is parallel to the side of the rectangle.
aivan3 [116]

Answer:

"The area of EFGH is always One-half of the area of the rectangle."

Step-by-step explanation:

<em>Graph is attached.</em>

<em />

The kite consists of 2 triangle, EFG and EHG.

The area of EFG:

\frac{1}{2}*EG*h

where h is the height from F to EG

The area of EHG:

\frac{1}{2}*EG*h_1

where h_1 is the height from H to EG

We also know that h + h _1 is the width of the rectangle and EG is the length of the rectangle

Thus,

Area of Kite = \frac{1}{2}*EG*h + \frac{1}{2}*EG*h_1 = RectangleLength*RectangleWidth

Also, Area of rectangle is rectangle length * rectangle width.

Thus, area of kite is always half of that of rectangle, the third choice is right.

5 0
3 years ago
Read 2 more answers
Maddy lleva un bote con bebida para deportistas; el bote de 5 55 litros pesa 7 , 5 kg 7,5 kg7, comma, 5, start text, space, k, g
Kaylis [27]

Answer: 3\ kilograms

Step-by-step explanation:

It is important to remember that, by definition, proportional relationships have the following form:

y=kx

Where "k" is the constant of proportionality.

 We know that Maddy assume that the relation between the volume and the weight is proportional.

Then, let be "V" the volume in liters and "w" the weight in kilograms.

We can write the following equation:

V=kw

 So, if the boat of 555 liters weights 7.5 kilograms, we can find "k":

555 =k(7)\\\\k=\frac{555}{7}\\\\k=74

In order to solve the exercise, substitute the value of "k" and V=222 into the equation and solve for "w". Then:

222=(74)w\\\\\frac{222}{74}=w\\\\w=3

7 0
3 years ago
Find the area of the shape if the radius is 10
Softa [21]

Answer:

314

Step-by-step explanation:

A=πxr^2

A=πx10x10

A=πx100

A=314

idk if im right. make sure to tell me

4 0
3 years ago
Gambles are independent, and each one results in the playerbeing equally likely to win or lose 1 unit. Let W denote the netwinni
san4es73 [151]

Answer:

P{W>0}=0.5

P{W=0}=0.25

E{W}=0

Step-by-step explanation:

<u>Given:</u>

Gambles are independent i.e. each player is equally likely to win or lose 1 unit. OR each player has equal probability to win or lose 1 unit.

Let W denote the net winnings of a gambler whose strategy is to stop gambling immediately after his first win.

Then

<u>A.P{W>0}=?</u>

P{W>0}=0.5, because each player is equally likely to win or lose on first gamble. i.e there is equal chances for winning or losing on the first gamble.

<u>B.P{W<0}=?</u>

for P{W<0} we need to find P{W=0} first as;

P{W=0}=0.25

As there is equal probability to win or lose, after first win, if you want to finish gamble with no profit (equal number of lose and win) then if you losing, you have equal probability to win or lose so to finish your game with P=0 your probability is 0.25 (half of 0.5)

P{W<0} means net lose which is equal to total probability minus probability of profit and probability of net profit equal to zero.

i.e. P{W<0}=1-P{W=0}-P{W>0}

P{W<0}=1-0.25-0.5=0.25

<u>C.E{W}=?</u>

E{W}=P{W>0}*{W>0}+P{W<0}*{W<0}+P{W=0}*{W=0}

E{W}=0.5*(1)+0.5(-1)+0.25*(0) (for any value of W,P{W>0}*{W>0}+P{W<0}*{W<0}=0, because sum of same positive and negative numbers is zero)

E{W}=0

8 0
3 years ago
In exercise 4 and 5 find the unkown or marked angles​
ohaa [14]

Answer:

Ф = 110°, β = 110°

Step-by-step explanation:

∠Ф and the 110° angle are corresponding angles since the vertical lines are parallel and a horizontal line cut across both lines. Thus Ф = 110°.

∠β and ∠Ф are alternate angles since the horizontal lines are parallel and a vertical line cut across both lines. Thus Ф = 110° and ∠β = 110°.

3 0
3 years ago
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