A bag of marbles has 5 blue marbles, 3 red marbles, and 6 yellow marbles. A marble is drawn from the bag at

According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next j

Ahat [919]

Complete Question

According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.

1 Which of the following statements is the correct alternative hypothesis?

2 The test statistic for testing the hypothesis is

a. -2.64

b. -2.32

c. -2.11

d. -1.28

e. none of these are correct

Answer:

1

The alternative hypothesis $H_a : \mu < 15.9$

2

The test statistics $z = -2.64$

Step-by-step explanation:

From the question we are told that

The population mean value for time citizens remain unemployed is $\mu = 15.9 \ weeks$

The sample size is n = 50

The sample standard deviation is 6.7 weeks.

The sample mean value for time citizens remain unemployed is $\mu = 15.9 \ weeks$

The null hypothesis is $H_o : \mu \ge 15.9$

The alternative hypothesis $H_a : \mu < 15.9$

Generally test statistics is mathematically represented as

$z = \frac{ \= x - \mu }{ \frac{s}{\sqrt{n} } }$

=> $z = \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}$

=> $z = -2.64$

7 0

3 years ago

The system of equations Y =-3x+2 and Y = 3x-6 is shown on the graph below.

Ira Lisetskai [31]

Answer:

A

Step-by-step explanation:

8 0

3 years ago

Evaluate 3ab for a = 2 and b = 3. 6 9 18

strojnjashka [21]

3ab...when a = 2 and b = 3

(3)(2)(3) = 6(3) = 18

4 0

3 years ago

Read 2 more answers

Determine which method works, substitution or elimination? 4x^2+3y^2=42x^2-6y^2=-3

GarryVolchara [31]

Given:

$\begin{gathered} 4x^2+3y^2=4 \\ \\ 2x^2-6y^2=-3 \end{gathered}$

Find the method .

Sol:

$\begin{gathered} 4x^2+3y^2=4..............(1) \\ \\ 2x^2-6y^2=-3.............(2) \end{gathered}$

2eq(1) + eq(2) then,

$8x^2+6y^2=8$

Then apply the elimination method.

$\begin{gathered} 8x^2+6y^2=8 \\ 2x^2-6y^2=-3 \\ --------- \\ 10x^2=5 \\ \\ x^2=\frac{5}{10} \\ \\ x=\sqrt{\frac{1}{2}} \end{gathered}$

3 0

1 year ago

Suppose a regular n-gon is inscribed in a circle of radius r. Diagrams are shown for n=6, n=8, and n = 12. n = 6 n=8 n = 12 a a

m_a_m_a [10]

Answer:If an N-gon (polygon with N sides) has perimeter P, then each of the

N sides has length P/N. If we connect two adjacent vertices to the

center, the angle between these two lines is 360/N degrees, or 2*pi/N

radians. (Do you understand radian measure well enough to follow me

this far?)

The two lines I just drew, plus the side of the polygon between them,

form an isosceles triangle. Adding the altitude of the isosceles

triangle makes two right triangles, and we can use one of them to

derive the equation

sin(theta/2) = s/(2R)

where theta is the apex angle (which I said is 2*pi/N radians), R is

the length of the lines to the center (the radius of the circumscribed

circle), and s is the length of the side (which I said is P/N).

Putting those values into the equation, we have

sin(pi/N) = P/(2NR)

so that

P = 2NR sin(pi/N)

gives the perimeter of the N-gon with circumradius R.

Can we see a connection between this formula and the perimeter of a

circle? The perimeter of the circumcircle is 2*pi*R. As we increase

N, the perimeter of the polygon should get closer and closer to this

value. Comparing the two, we see

2NR*sin(pi/N) approaches 2*pi*R

N*sin(pi/N) approaches pi

You can check this out with a calculator, using big numbers for N such

as your teacher's N=1000. If you calculate the sine of an angle in

degrees rather than radians, the formula will look like

N*sin(180/N) --> pi

Step-by-step explanation:

6 0

3 years ago