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Ludmilka [50]
3 years ago
13

Jeremy is randomly selecting ans outfit to celebrate probability day at his school.He can chose from a green or purple shirt, de

nim or khaki pants, argyle or crew socks, and boots, flip-flops or sneakers. what is the probability that Jeremy will select an outfit that includes flip-flops and argyle socks?
Mathematics
1 answer:
viva [34]3 years ago
8 0
Jeremy can choose his outfit in following ways:
2 ways to select a shirt
2 ways to select a pant
2 ways to select socks
3 ways to select the footwear.

Total number of ways to select the dress = 2 x 2 x 2 x 3 = 24 ways

Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants. The shirt is not specified, so the shirt can be any.

So there are 2 ways to select a shirt, 1 way to select the pant, socks and footwear. So Jeremy can select the desired outfit in 2 ways.

Thus, the probability that Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants = 2/24 = 1/12
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Step-by-step explanation:

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What is the slope of the line on the graph
cupoosta [38]

Answer:

The answer is 1/2. Hope that helps

Step-by-step explanation:

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3 years ago
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I need help pleessse
wariber [46]

Answer:

1.  8/3

2.   1/7

3.  1/12

4.  1/27

Step-by-step explanation:

1.  3/8 * m = 1

Multiply by 8/3

8/3 * 3/8 m = 1* 8/3

m = 8/3


2.  7 * m = 1

Divide by 7

7*m /7 = 1/7

m = 1/7


3.  3 ÷m = 36

Multiply by m

3 ÷m * m = 36*m

3 = 36*m

Divide by 36

3/36 = 36*m/26

1/12 = m


4.  4/9 ÷m = 12

Multiply by m

4/9 ÷m * m = 12*m

4/9 = 12*m

Multiply by 1/12

4/9 *1/12 = 12*m * 1/12

4/12 *1/9 = m

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1/27

4 0
3 years ago
Ken painted 14 meters of fencing in 1 hour. How many centimeters of fencing can he paint in 45 minutes?
Andrew [12]

Answer:

.

Step-by-step explanation:

3 0
2 years ago
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yo can someone pls help me with this i’ve been crying for the last hour bc i can’t figure it out and it’s due in 30 minutes. the
mr Goodwill [35]

9514 1404 393

Answer:

  • area: 524 cm²
  • perimeter: 124.8 cm

Step-by-step explanation:

The rectangle in the middle has a width equal to the radius of the semicircular ends, so (20 cm)/2 = 10 cm.

The semicircular ends, together, make a complete circle of radius 10 cm.

The area is the sum of the areas of the parts:

  A = LW = (21 cm)(10 cm) = 210 cm² . . . . . . rectangle area

  A = πr² = π(10 cm)² = 100π cm² ≈ 314 cm² . . . . . circle area

The total area is ...

  210 cm² +314 cm² = 524 cm² . . . . area of the figure

__

The perimeter of the figure is the sum of the lengths of all of the edges. From the left, working clockwise, we have ...

  P = (1/2 circle of diameter 20) + (rectangle top = 21) +(1/2 circle of diameter 20) +(circle radius = 10) +(rectangle bottom = 21) +(circle radius = 10)

The two 1/2 circles add to a whole circle with a circumference of ...

  C = πd = (3.14)(20 cm) = 62.8 cm

Then the whole perimeter is ...

  P = 62.8 cm + 21 cm + 10 cm + 21 cm + 10 cm = 124.8 cm

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Note that we have used 3.14 for pi. If you use a more exact value, your answers will be slightly different.

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