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sleet_krkn [62]
2 years ago
10

Which is a factor of both terms of the expression 2d-10

Mathematics
1 answer:
zysi [14]2 years ago
7 0

Answer:

<h2>2</h2>

Step-by-step explanation:

2d = 2 · d

10 = 2 · 5

2d - 10 = 2 · d - 2 · 5 = 2 · (d - 5)

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What is the slope of a line between the points (-4,-3) and (4, -2)?
Mashcka [7]

Answer:

slope is 1/8

Step-by-step explanation:

you have to substitute the values of x and y into the equation below:

after simplifying your answer would be 1/8

4 0
3 years ago
What is the prime factorization of 96?<br> 0 25.32<br> 25.3<br> 02.2.2.2.3<br> 8.12
Nina [5.8K]

Answer:

8.12

Step-by-step explanation:

we first multiply 8 by 12 and we will get 96 as our answer

7 0
3 years ago
PLEASE HELP! GIVEE ME THE 14 ANSWERS FOR THIS FOR BRAINLIEST
gulaghasi [49]

Answer:

Step-by-step explanation:

oh boy

1) 9 < 16

2) -4 < 5

3) 18 > -19

4) -38 < -16

5) 6 > 4

6) -14 > -25

7) -45 > -55

8) -2 > -10

9) -4, -1, 1, 3, 6

10) -15, -13, -5, 8

11) -9, -6, -5, -1, 0

12) -4, -2, 1, 3

13) -10, -9, 7, 8, 11

14) -33, -25, -14, -4, 7

hope this helps <3

6 0
3 years ago
Please help I cannot-
Dmitry [639]

Answer:

1922 m cubed

Step-by-step explanation:

Not gonna do that, I did the work and checked it. Should be right

5 0
3 years ago
Read 2 more answers
L1 : y = 2x , (2) find the equation of the line L2 perpendicular to L1 passing through the point P = (1, 2).
just olya [345]

Answer:

<h2>2y+x = 5</h2>

Step-by-step explanation:

Given the line L1 as y = 2x perpendicular to an unknown line L2 passing through the point P = (1, 2), we are to find the equation of line L2. to find the equation of the line L2, we will use the point-slope equation of a line expressed as y-y₀ = m(x-x₀)

m is the slope of the unknown line

(x₀, y₀) is the given point.

First is to get the slope of the known line:

comparing the line L1: y = 2x with the standard equation of the line y = mx+c, it can be seen that m = 2

Then we will calculate the slope of the required line.

Since L1 is perpendicular to L2, the product of their slope will be -1 i.e

mm₁ = -1 where m₁ is the slope of the required line L2.

Given m =2

m₁ = -1/m

m₁ = -1/2

Finally we will calculate the equation of line L2 by substituting the slope of line L2 and the point in the point slope equation above;

y-y₀ = m(x-x₀)

Given (x₀, y₀) = (1,2) and m₁ = -1/2

y-2 = -1/2(x-1)

open the parenthesis

y-2 = -x/2+1/2

multiply through by 2:

2y-4 = -x+1

2y+x = 1+4

2y+x = 5

<em>Hence the equation of the line L2 is 2y+x = 5</em>

<em></em>

8 0
3 years ago
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