2 years ago

Which is a factor of both terms of the expression 2d-10

Mathematics

1 answer:

zysi [14]2 years ago

7 0

Answer:

Step-by-step explanation:

2d = 2 · d

10 = 2 · 5

2d - 10 = 2 · d - 2 · 5 = 2 · (d - 5)

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One fifth plus one tenth equals what

CaHeK987 [17]

Answer:

3/10, or 0.3, or 30%

Step-by-step explanation:

1/5=2/10

2/10+1/10=3/10

6 0

3 years ago

Read 2 more answers

Please help … will mark brainliest

vlada-n [284]

Answer:

k = 3

Step-by-step explanation:

Expanding the first term, we find 1/x at 10(kx)²(1/x)³ = 10k²/x

Expanding the first term, we find 1/x at 8*1⁷(-2/x)¹ = -16/x

Then

10k² - 16 = 74

k = 3

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2 years ago

Which expression is equivalent to find f(0)<br> f(x) = -9 (3) ^x<br> f(0)=

ankoles [38]

x = 0

f(x) = -9(3)^0

Anything to the power of 0 is 1,

f(x) = -9(1)

f(x) = -9

The answer is -9

Hope this was useful :)

6 0

2 years ago

Jessica wants to start making and selling bracelets using colorful beads and thread. She starts collecting information to come u

evablogger [386]

Answer:

1. $290

2. $1.50

3. $3.50

4 0

2 years ago

Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis

Mariana [72]

Answer:

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago