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astraxan [27]
3 years ago
11

Find the mean of the given data, 5.6, 5.2, 4.6, 4.9, 5.7, 6.4

Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

5.4

Step-by-step explanation:

5.6 + 5.2 + 4.6 + 4.9 + 5.7 + 6.4 = 32.4

32.4 / 6 = 5.4

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How do i solve this equation 5x-3y=12 for y
I am Lyosha [343]
We have such equation
5x-3y=12          /-5x  (subtract 5x both sides)
5x-5x-3y=12-5x    
-3y=-5x+12          /:3   divide both sides by 3
-y=\frac{-5x+12}{3}      /*(-1)     multiply both sides by -1
y=-\frac{-5x+12}{3}
y=\frac{5x-12}{3} - its the answer
6 0
3 years ago
Please help ASAP!!!!!!!
JulsSmile [24]

Answer:

  $86.81

Step-by-step explanation:

Using the given formula, we want to compute A for ...

  P = 4750

  r = 0.2279

  n = 365 . . . . . assuming "exact" interest

  t = 1 or 30

For 1 day late:

  A = 4750(1 +0.2279/365)^(365·(1/365)) = 4752.97

For 30 days late:

  A = 4750(1 +0.2279/365)^(365·(30/365)) = 4839.78

The difference in these payment amounts is ...

  $4839.78 -4752.97 = $86.81

You would save $86.81 in interest charges by paying only 1 day late.

_____

<em>Comment on the question</em>

It would be a poor choice of credit card to use one that compounds interest daily. Most do so on a monthly basis.

5 0
3 years ago
Read 2 more answers
20 points and I will mark you brainliest!
irina [24]
Is there supposed to be a picture??
3 0
2 years ago
Read 2 more answers
What is the inequality that would represent: The sum of two numbers is<br> less than 4?*
MArishka [77]

Answer:

x+y<4

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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