Its OP I am working on this right now and got a hundred on a topic test i would know
<u>Answer with explanation:</u>
As per given , we have
A sample of 50 gribbles finds an average length of 3.1 mm with a standard deviation of 0.72.
i.e. n= 50
Degree of freedom = n-1=49


The point estimate of the population mean is equals to the sample mean.
i.e. The best estimate for the length of gribbles= 3.1 mm
Also, population standard deviation is unknown , then the confidence interval would be :

For df= 49 and significance level of 0.05 , the t- value (using t-distribution table) would be :

Now, Margin of error : 

95% confidence interval : 

Answer:
none of the chartacier
Step-by-step explanation:
The second one is correct. 66/300 = x/100
Answer:
I believe the answer is A. m + 68 = 185; m = 117
Step-by-step explanation: