A battery with

Mathematics

2 answers:

drek231 [11]3 years ago

7 0

Answer:

Given,

The original percentage of battery = 20 %,

Also, Every minute that passes, an additional 5%,

So, the increment in percentage after x minutes = 5x percentage

Thus, the final battery after x minutes = ( 20 + 5x ) %

Let y represents the total percentage of battery after x minutes,

⇒ y = 20 + 5x

Which is the required function that shows the given situation.

For graphing,

y = 20 + 5x is a line having x-intercept = (-4,0)

And, y-intercept = (0,20)

Also, battery's capacity and time can not be negative,

⇒ x ≥ 0 , y ≥ 0

horrorfan [7]3 years ago

5 0

Y = 5x + 20

Start at (0, 20).
Then plot a point at (1, 25).

The line should be going through points (2, 30), (3, 35), (4, 40), (5, 45), etc.

For every time the x number goes up, the y number goes up 5 times for the 5%.

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Type the correct answer in the box. Write the standard form of the quadratic equation modeled by the points shown in the table b

White raven [17]

Y =ax² + bx +c

1) Point (0,7)

7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7

2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b

4) a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2

5) a+b= - 3
2 + b = -3
b = -5

y=2x² - 5x + 7