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pantera1 [17]
3 years ago
7

Geno started to evaluate 90 − (18 + −2)(−3), as shown. What should he do next?

Mathematics
2 answers:
frez [133]3 years ago
5 0

Answer:

bb12b1 exatlet

Step-by-step explanation:

Allisa [31]3 years ago
4 0
Simplify (18+-2) to 90-(16)(-3)
Multiply (16)(-3) -> -48
Simplify 90-48
Answer is 42
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Solve for x in both!!!!!
zvonat [6]

Answer:

- 2(x - 2) - 4x = 3(x + 1) - 9x \\  - 2x + 4 - 4x = 3x + 3 - 9x \\ 9x - 3x - 2x - 4x = 3 - 4 \\ 9x - 9x =  - 1 \\ 0x =  - 1 \\ 0 =  - 1

So ; No solution

___o___o____

5(x + 2) - 3 = 3x - 8x + 7 \\ 5x + 10 - 3 =  - 5x + 7 \\ 5x + 7 =  - 5x + 7 \\ 5x + 5x = 7 - 7 \\ 10x = 0 \\  \\ x =  \frac{0}{10}  \\  \\ x = 0

I hope I helped you^_^

4 0
3 years ago
Read 2 more answers
Edit: I figured it out, it's 14+7(sqrt sign) 2
Anettt [7]

Answer:

Perimeter = 14 + 7\sqrt{2}

Step-by-step explanation:

Given:

Area of the square = 49 in²

Required

Determine the perimeter of the one of the congruent triangles

First, we'll determine the length of the square;

Area = Length * Length

Substitute 49 for Area

49 = Length * Length

49 = Length^2

Take Square root of both sides

7 = Length

Length = 7

<em>When the square is divided into two equal triangles through the diameter;</em>

<em>2 sides of the square remains and the diagonal of the square forms the hypotenuse of the triangle;</em>

Calculating the diagonal, we have;

Hypotenuse^2 = Length^2 + Length^2 -- Pythagoras Theorem

Hypotenuse^2 = 7^2 + 7^2

Hypotenuse^2 = 2(7^2)

Take square root of both sides

Hypotenuse = \sqrt{2} * \sqrt{7^2}

Hypotenuse = \sqrt{2} * 7

Hypotenuse = 7\sqrt{2}

The perimeter of one of the triangles is the sum of the 2 Lengths and the Hypotenuse

Perimeter = Length + Length + Hypotenuse

Perimeter = 7 + 7 + 7\sqrt{2}

Perimeter = 14 + 7\sqrt{2}

7 0
4 years ago
Dilate line f by a scale factor of 3 with the center of dilation at the origin to create line f'. Where are points A' and B' loc
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

(D). The locations of A' and B' are A' (0, 6) and B' (6, 0); lines f and f' are parallel.

8 0
3 years ago
A line passes through the points (p, a) and (p, –a) where p and a are real numbers. If p=0, what is the y-intercept? Explain you
Vsevolod [243]
The slope of the line passing through the points A(a, b), and B(c, d), is given by 
                               \displaystyle{ m=\frac{d-b}{c-a},

thus, the slope of the line through <span>points (p, a) and (p, –a) is 

                               </span>\displaystyle{ m=\frac{-a-a}{p-p}=\frac{-2a}{0}.

When applying the slope formula results in division by zero, this means that the line is a vertical line.

This could have also been noticed directly, since the line contains 2 points with the same x-coordinate. 

The equation of this line is x=p, since the x-coordinate is always p, no matter what y is.

If p=0, then the equation of the line is x=0, which is the y-axis itself. In this case, the y-intercept is the whole y-axis.

Answer: The whole y-axis.




7 0
4 years ago
Choose the correct conic section to fit the equation. X^2/9+y^2/4=1
andreyandreev [35.5K]
It is Hyperbola I believe:)
8 0
3 years ago
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