Dilate line f by a scale factor of 3 with the center of dilation at the origin to create line f'. Where are points A' and B' loc
ated after dilation, and how are lines f and f' related?
The locations of A' and B' are A' (0, 2) and B' (6, 0); lines f and f' intersect at point A.
The locations of A' and B' are A' (0, 6) and B' (2, 0); lines f and f' intersect at point B.
The locations of A' and B' are A' (0, 2) and B' (2, 0); lines f and f' are the same line.
The locations of A' and B' are A' (0, 6) and B' (6, 0); lines f and f' are parallel.
The locations of A' and B' are A' (0, 2) and B' (6, 0); lines f and f' intersect at point A.
The locations of A' and B' are A' (0, 6) and B' (2, 0); lines f and f' intersect at point B.
The locations of A' and B' are A' (0, 2) and B' (2, 0); lines f and f' are the same line.
The locations of A' and B' are A' (0, 6) and B' (6, 0); lines f and f' are parallel.
1 answer:
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Answer:
Yes, the line intersects the parabola two times at the points (0,0) and (-1,-1)
Step-by-step explanation:
Hi there!
We have the following system of equations:
y = x
y = -x²
If the curves intersect, then there is at least a pair (x,y) that satisfies both equations. That will only happen for those values of x for which:
-x² = x
The only two values that satisfy that equality are 0 and -1.
When x = 0, y is also 0 for both functions. In the same way, when x = -1 y is also -1 for both functions. Then, the curves will intersect at the points (0, 0) and (-1, -1).
Please, see the attached graphic for a better understandign of the problem.
Have a nice day!
