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3 years ago

You had 250 minutes left on your cellphone and you talk an hour a week

Mathematics

1 answer:

hjlf3 years ago

3 0

Let w = the number of weeks you talked on your cell phone

60 min = 1 hr

60w + 250 = total number of minutes

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Find the sum and express it in simplest form.

m_a_m_a [10]

3b - 7u -5

Add them together and put them in alphabetical order.

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2 years ago

What is the slope of the line that passes through the points (-8, -6)and (-18, 6) ? Write your answer in simplest form.

djyliett [7]

Answer:

-6/5

Step-by-step explanation:

You are going down 6 units and 5 units to the direction of the point you get .

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3 years ago

The following function represents the value of a car, in dollars, after x years:

Assoli18 [71]

Answer:

Option D.The decrease in the value of the car, which is 8%

Step-by-step explanation:

we have a exponential function of the form

$f(x)=a(b)^{x}$

where

y is the value of the car

x is the time in years

a is the initial value

b is the base

r is the rate of decrease

b=1+r

In this problem we have

a=$24,000 initial value of the car

b=0.92

0.92=1+r

r=0.92-1=-0.08=-8%-----> is negative because is a rate of decrease

8 0

2 years ago

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Natali5045456 [20]

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2 years ago

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

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2 years ago