Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>
According to the question,
- Diameter of circle = 16 in
We are asked to calculate it’s circumference in terms of π.
★ Circumference of circle = 2πr
___________________________________
Let us first calculate the radius of the circle.
→ Diameter = 2 × Radius
→ 16 in = 2r
→ r = 16 in ÷ 2
→ r = 8 in
___________________________________
Substituting values in the formula of circumference,
→ C = 2πr
→ C = (2 × π × 8) in
→ C = 16π in
<u>Therefore</u><u>,</u><u> </u><u>1</u><u>6</u><u>π</u><u> </u><u>inches</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
m=(r/n)+0.114r
Step-by-step explanation:
m=monthly payment
r=remaining amount
n=# of months remaining
Answer:
The solution to the system of equations is (1.6,-2)
Step-by-step explanation:
You have to plug the x which is -2 into the equation.
You would get y=2/3(-2)+3
Then you would calculate that to get y=1.6
Lastly you combine the y answer to the x answer to get the coordinates (1.6,-2)
X/7 = 6/4.2
4.2x = 42
x= 10
