ew, no you can not do that. That is really nasty .
Answer:
it's got to do something with milk I guess it's the sugary substance found in milk and it's a compound
Answer:
The number of molecules is 1.4140*10^24 molecules
Explanation:
To know the number of molecules, we need to determine how many moles of water we have, water has molar mass of 18.015g/mol
This means that one mole of water molecules has a mass of 18.015g.
42.3g * 1 mole H2O/18.015g
= 2.3480 moles H2O
We are using avogadros number to find the number of molecules of water
2.3480 H2O * 6.022*10^ 23moles/ 1mole of H2O
That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O
Number of molecules = 1.4140 *10^24 molecules
Its okay my friend. you dont need to over stress it.
The given question is incomplete. The complete question is
If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.
Answer: The equilibrium concentration of
is 0.498 M
Explanation:
Initial concentration of
= 1.0 M
The given balanced equilibrium reaction is,

initial (1.0) M 0 0
At eqm (1.0-2x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[H_2]\times [I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
Now put all the given values in this expression, we get :

By solving we get :

Thus the equilibrium concentration of
is 0.498 M