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2 years ago

Is c7h16+o2→co2+8h2o+7co2 a balanced equation

Chemistry

1 answer:

erik [133]2 years ago

7 0

<span>C7H16 + 11 O2 = 7 CO2 + 8 H2O

If you write it like this then it is balanced.</span>

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The pK of acetic acid is pK = 4.76. For a 0.1 M solution of acetic acid at a pH = 4.76 what is the concentration of [H+]?

spin [16.1K]

Answer:

[H+] = 1.74 x 10⁻⁵

Explanation:

By definition pH = -log [H+]

Therefore, given the pH, all we have to do is solve algebraically for [H+] :

[H+] = antilog ( -pH ) = 10^-4.76 = 1.74 x 10⁻⁵

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3 years ago

A student mixes some sugar into a cup of hot water. The sugar dissolves in the liquid. What are the BEST ways for the student to

polet [3.4K]

You would have to evaporate the water to get just the sugar

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2 years ago

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.

lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer : The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken for decay process = 9.00 year

a = initial amount or moles of the reactant = 1.000 g

a - x = amount or moles left after decay process = 0.805 g

Putting values in above equation, we get:

$k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}$

$k=0.0241\text{ year}^{-1}$

To calculate the half-life, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=28.8\text{ years}$

Therefore, the half-life of strontium-90 is 28.8 years.

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2 years ago

Equal amounts of four gases are placed in identical containers at the temperatures that are noted below. Samples of Gases at Dif

Alborosie

Answer : S) 33.2 °C

Explanation : When the equal amounts of gases are placed in identical containers but subjected to different temperatures would exert pressure in different amount which will in turn increase the rate of collision between the molecules of gas.

So, when the temperature is increased to maximum greater amount of force would be exerted and the gas molecules will collide with a larger force. Hence the answer will be as the highest temperature i.e. 33.2 °C

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3 years ago

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docker41 [41]

True

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