What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?

1 answer:

5 0

Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
$pV=nRT \\ or \\ V= \frac{nRT}{p}$
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
$V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}$

Answer: 0.363 m³

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