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babunello [35]
4 years ago
11

What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?

Chemistry
1 answer:
Zina [86]4 years ago
5 0
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
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What year did mendeleev organized his periodic table in order of increasing atomic number
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Mendeleev organized his periodic table in order of increasing atomic number in 1869.

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4 years ago
Which of these things would you expect to have cells with both mitochondria
Allushta [10]

Answer:

D. Grass​

Explanation:

Every living organism must contain one or more cells to be considered "living". Each cell, however, contains certain structures that perform specific roles called ORGANELLES. These organelles are of different types and hence, perform different tasks. For example, mitochondria is the power house of a cell i.e. site of energy production, and hence, is found in every eukaryotic cell.

On the other hand, chloroplast is an organelle designed to perform photosynthesis, which only occurs in plant cells. Since only plant cells can undergo photosynthesis, only plant cells can contain chloroplast. Hence, according to this question, GRASS as a type of plant is an organism that will contain both mitochondria and chloroplast in its cells.

6 0
3 years ago
Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.
nlexa [21]

Answer:

The answer is

<h2>1.38 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

density =  \frac{138}{100}  = \frac{69}{5 0}

We have the final answer as

<h3>1.38 g/mL</h3>

Hope this helps you

7 0
3 years ago
When the ph of the extracellular fluid drops, the kidneys
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5 0
3 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
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