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2 years ago

14

consider the reaction between acetylene C2H2 and oxygen in a welding torch 2C2H2 + 5O2 = 4CO2 + 2H2O of 5.4 moles of acetylene r

eact with sufficient oxygen how many grams of CO2 should form

1 answer:

Eddi Din [679]2 years ago

5 0

Answer:

C. 4.8*10² g.

Explanation:

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it forms a covalent bond

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How can the rescue workers get enrgy to the batteries in their equipment during rescue missions.

Ipatiy [6.2K]

Answer:

a generator that allows them to convert kinetic energy into potential energy

Explanation:

Rescue workers can accomplish this by using a generator that allows them to convert kinetic energy into potential energy. Such as a crank generator, with these, they spin a crank with their hands and the generator takes that kinetic energy that is building up through the work that the rescuer is exerting and converts it to potential electric energy that can properly be used to provide energy to the batteries for their equipment. This is what is generally used for situations such as what rescuers go through when there is no electricity around.

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2 years ago

Which describes the molecule below?

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Answer:

Option D. A liquid with three unsaturated fatty acids.

Explanation:

A careful observation of the molecule given in question shows that the molecule is unsaturated as all three fatty acid that make up the compound contain double.

Double is a characteristic property of unsaturated compound.

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2 years ago

The nucleus is held closely together by?

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3 years ago

A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill

LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

$BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)$

$Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)$

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

$\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%$

This means in 10.0 g, we have a total of:

$m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g$ of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

$\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%$

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

if this number is equal to 6.595 g, we have a pure sample of barium chloride;
if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.

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3 years ago