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3 years ago

A 200 kg object accelerates at a rate of 5.5 m/s2 calculate the force required to produce this acceleration.

Chemistry

1 answer:

alexandr402 [8]3 years ago

6 0

Answer:

Explanation:

F=ma

m=200 Kg

a=5.5 m/s2

F=ma

F=200*5.5 =1100 N

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A stable atom that has a large nucleus most likely contains

maria [59]

Answer:

3. Equal numbers of protons and neutrons

Explanation:

The nucleus becomes unstable if the ratio of protons to neutrons is less than 1:1 or more than 1:1.5.

The most stable nucleus has a neutron proton ratio of 1:1 which means that they can not release a neutron or a proton to decay.

Nucleus 3 is therefore the most stable.

8 0

3 years ago

Convert a density of 7.2 g/ml into the unit kg/L

aivan3 [116]

Unit conversion is a multi-step process, in which division or multiplication by a numeral factor is involved.

Density = $7.2 g/mL$ (given)

Since, $1 g = 0.001 kg$ and

$1 mL = 0.001 L$

Now, converting $7.2 g/mL$ to $kg/L$ :

$7.2 \frac{g}{mL}\times \frac{1 kg}{1000 g}\times \frac{1000 mL}{1 L}$

= $7.2 kg/L$ .

Hence, density is $7.2 kg/L$ .

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3 years ago

Find the volume of 20g of benzene

sergey [27]

(d) Density of Benzene: 0.8786 g/cm cubed

(m) Mass: 20.00g

Formula to solve (v) volume of benzene: V=m/d

V=20g / 0.8786g/cm cubed

Answer: Volume of benzene is: 22.8 cm cubed

Explanation: Well, density is mass divided volume. In this, it is what the volume is. All you need is mass divided by density. Hope this helps!

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4 years ago

HELP! 40 POINTS

xxTIMURxx [149]

Answer:

idk neeed help to

Explanation:

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4 years ago

When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.

inessss [21]

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

E = Energy of 1 photon = $4.30\times 10^{-19}J$

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = ?

Putting values in above equation, we get:

$4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm$

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0

3 years ago