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strojnjashka [21]
2 years ago
9

A student observes two strips of magnesium, mg ribbon that are each 3cm long. One strip of magnesium

Chemistry
1 answer:
ankoles [38]2 years ago
6 0

Therefore option c , i.e. The substances in both test tubes are reactive only at high temperatures. is the only statement which is NOT supported by the student's observations.

<h3>What is the reaction between Magnesium and Hydrogen ?</h3>

Magnesium reacts with hydrochloric acid to produce hydrogen gas

Mg (s) + 2 HCl (aq) → MgCl₂ (aq) + H₂ (g)

In this reaction, the magnesium and acid are gradually used up , which can be seen in the test tube 2 .

A chemical reaction is taking place in Test tube 2 ,

Hydrogen gas is released in test tube 2 ,

Energy is released in the reaction involving hydrochloric acid and we can see in test tube 2 the reaction is going on

therefore option C i.e. The substances in both test tubes are reactive only at high temperatures. is the only statement which is NOT supported by the student's observation.

To know more about the chemical reaction between Magnesium and Hydrogen and this test.

brainly.com/question/19062002

#SPJ4

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620 mL of nitrogen at standard pressure is compressed into a 480 mL container. What is the new pressure in kPa?
bulgar [2K]

Answer:

c. 131 kPa

Explanation:

Hello!

In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:

P_1V_1=P_2V_2

Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}=\frac{620mL*101.325kPa}{480mL}\\\\P_2=131kPa

Therefore, the answer is c. 131 kPa .

Best regards!!

7 0
2 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
HELP WILL GIVE BRAINLIEST!
Lostsunrise [7]

Answer:

cover the taste with sugar add two times the amount your supposed to put in

Explanation:

3 0
3 years ago
Bob walks 81m East and then he walks 103m West.
kogti [31]

The Answer your looking for is

He walked  the distance of: = 184 m

4 0
3 years ago
Read 2 more answers
Select the keyword or phrase that will best complete each sentence.
pishuonlain [190]

Answer:

1) acetylide

2) enol

3) aldehydes

4) tautomers

5) alkynes

6) Hydroboration

7) Keto

8) methyl ketones

Explanation:

Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.

Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.

The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.

3 0
3 years ago
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