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Flura [38]
3 years ago
7

Sheela wants to make a computer model of a land ecosystem. Part of her model simulates the chemical processes of photosynthesis

that involve the creation of sugars. Which of these chemical processes are these?
A. the light-dependent reactions
B. the light-independent reactions
C. the dark reactions
D. the reactions in the mitochondria
Chemistry
2 answers:
shusha [124]3 years ago
5 0
<span>The correct answer is A, the ligt-dependent reactions. These reactions are responsible for the production of glucose molecules, by the utilization of carbon dioxide, and water along with the sunlight. Glucose is then broken down during resiration process, for the production of ATP in mitochondria.</span><span />
dybincka [34]3 years ago
5 0

B. the light-independent reaction is the correct answer in Edgen

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Mendeléyev diseño su tabla casi al mismo tiempo que un químico alemán llamado Julius Lothar Meyer, quien la publicó un año despu
lord [1]

Answer:

Mendeléyev designed his table around the same time as a German chemist named Julius Lothar Meyer, who published it a year later. However, finally Mendeléyev's order was imposed. Do you know what his great success was? Help plis.

Mendeleev predicted the existence and properties of unknown elements that he called eka-aluminum, eka-boron, and eka-silicon, his table is based on atomic weight.

Explanation:

Gallium, scandium, and germanium were later discovered to coincide with his predictions. In addition to the fact that Mendeleev's table was published before Meyers, his work was more extensive, predicting the existence of other elements not known at the time.

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3 years ago
What are the representative elements? Where are they located
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The representative elements are elements where the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3–11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.
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Which of these is true about a pH meter?
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The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

\frac{dA}{dt}= kA

\Rightarrow \frac{dA}{A}=kdt

Integrating both sides

ln A= kt+c₁

\Rightarrow A= e^{kt+c_1}

\Rightarrow A=Ce^{kt}         [e^{c_1}=C]

The initial condition is A(0)= A₀,

\therefore A_0=Ce^{0.k}

\Rightarrow C=A_0

\therefore A=A_0e^{kt}.........(1)

Given that the Pb_{209}  has half life of 3.3 hours.

For half life A=\frac12 A_0 putting this in equation (1)

\frac12A_0=A_0e^{k\times3.3}

\Rightarrow ln(\frac12)= 3.3k     [taking ln both sides, ln \ e^a=a]

\Rightarrow k=\frac{ln \frac12}{3.3}

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

\therefore 0.2=1e^{(-0.21)\times t}

\Rightarrow e^{-0.21t}=0.2

\Rightarrow -0.21t= ln(0. 2)

\Rightarrow t= \frac{ln (0.2)}{-0.21}

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

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bc

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