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malfutka [58]
3 years ago
10

Christopher is 20 years younger than Ishaan. Ishaan and Christopher first met two years ago. Fourteen years ago, Ishaan as old a

s Christopher. How old is Christopher?

Mathematics
2 answers:
OverLord2011 [107]3 years ago
6 0

Answer:

24 years

Step-by-step explanation:

Go through the image attached to understand it properly

kvasek [131]3 years ago
5 0

Answer:

24 years

Step-by-step explanation:

Let Christopher's age=c

Since Christopher is 20 years younger than Ishaan.

Ishaan's age=c+20

Fourteen years ago, Ishaan was three times as old as Christopher.

Their ages 14 years ago are:

For Christopher: c-14

For Ishaan: (c+20)-14

Therefore:

3(c-14)=c+6

3c-42=c+6

3c-c=6+42

2c=48

Divide both sides by 2

c=24

Christopher is 24 years old.

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Answer:5(4a+9)

Step-by-step explanation:

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Richard wants to find out his current grade in math dass after taking five quizzes. Which measure of center
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Answer:

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3 years ago
The population of a city on April 15, 1915, was 47,175. During the period between March 1 and July 1, 1915, 1,325 new cases of s
Norma-Jean [14]

Answer:

the incidence rate is 28.47

Step-by-step explanation:

The computation of the monthly incident rate of active cases is shown below:

Incidence rate is

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= 28.47

hence, the incidence rate is 28.47

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3 years ago
Write a rule to describe the function shown. x y −6 −4 −3 −2 0 0 3 2 y equals start fraction two over three end fraction x y equ
sertanlavr [38]

Answer:

y=\frac{2}{3} x (y equals start fraction two over three end fraction x)

Step-by-step explanation:

Lest's organize the table values of our function first:

x    y

-6  -4

-3  -2

0   0

3   2

The simplest kind of of function is a linear function of the form y=mx+b where m is the slope and b is the y-intercept. Let's us check if our function is a linear one finding its equation and checking that all points are in the line.

The first step to find a linear equation is find the slope of the line; to do it, we are using the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

where

m is the slope of the line

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

We know from our table that the first and second points are (-6, -4) and (-3, -2) respectively, so x_1=-6, y_1=-4, x_2=-3, and y_2=-2.

Replacing values:

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-2-(-4)}{-3-(-6)}

m=\frac{-2+4}{-3+6)}

m=\frac{2}{3)}

Now that we have the slope of our line we can use the point slope formula to complete our linear function:

y-y_1=m(x-x_1)

where

m is the slope

(x_1,y_1) are the coordinates of the first point

Replacing values:

y-y_1=m(x-x_1)

y-(-4)=\frac{2}{3)}(x-(-6))

y+4=\frac{2}{3)}(x+6)

y+4=\frac{2}{3} x+4

y=\frac{2}{3} x+4-4

y=\frac{2}{3} x

Now, to check if our function is valid, we can either check if each point satisfies the rule y=\frac{2}{3} x, or we can graph it and check if each lies is in the graph.

Let's check both:

We already know that points (-6, -4) and (-3, -2) satisfy the rule (after all, those were the point we used to came out with the rule in the first place), so we just need to check the points (0, 0) and (3, 2)

- For (0, 0):

y=\frac{2}{3} x

0=\frac{2}{3}(0)

0=0

The point satisfies the rule.

- For (3, 2):

y=\frac{2}{3} x

2=\frac{2}{3} (3)

2=2

The point satisfies the rule.

Since all the points of our table satisfies the rule y=\frac{2}{3} x, we can conclude that the rule describing the function shown is y=\frac{2}{3} x.

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