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ivann1987 [24]
2 years ago
15

Which of the following relations is not a function?

Mathematics
2 answers:
SashulF [63]2 years ago
8 0
Hello,


Answer A: 2 has two pictures (values)


Novay_Z [31]2 years ago
8 0

Answer:

a

Step-by-step explanation:

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Kara owns 3 2⁄7 acres of farming land. She grows carrots on 1⁄6 of the land. On how many acres of land does Kara grow carrots?
kotegsom [21]

Answer:

can i have brainliest plssssssssssss im new here

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
n^2-2n-3 where n is the number of key rings in thousands, find the number of key rings sold when the profits is $5,000
ArbitrLikvidat [17]

Answer:

For the profit of $5,000, the key chains made is n = 4,000.

Step-by-step explanation:

Here the given expression , where: n = Number of key rings in thousands is given as:

P(n)  =   n²- 2 n - 3

Now, Profit is given to be $5,000.

Also, as we know 5000 = 5  x (1,000)

⇒  n²- 2 n - 3 = 5

Now, solving the above expression for the value of n, we get:

n^2 -  2 n - 3 = 5\\\implies  n^2  -2n - 8  =  0\\\implies  n^2  -4n +  2n - 8  =  0\\\implies n(n-4)  + 2(n-4)  = 0\\\implies (n-4) (n+2)  = 0

So, n = 4, OR , n = -2

Now, as n = The number of key chains. So it CANNOT BE NEGATIVE.

So,  n=  4  =  4 x (1,000)  = 4,000 key rings.

Hence, for the profit of $5,000, the key chains made is n = 4,000.

8 0
3 years ago
What is the volume of the figure below? 9 feet 4 feet 5 feet 0 30ft 0 608 90 ft ​
djyliett [7]

Answer:

120 ft³

Step-by-step explanation:

volume= \frac{2}{3}(l×w×h)

           =\frac{2}{3} (9×4×5)

           = 120 ft³

4 0
2 years ago
A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen
Darina [25.2K]

Answer:

100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

H=3^2=9\ ft

So, the height of top of tank is, y(3)=H=9\ ft

Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

Now, area of cross section of the tank is given as:

A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, y=x^2

So, x=\sqrt y

Therefore, radius, r=\sqrt y

Now, area of cross section is, A(y)=\pi (\sqrt y)^2

Work done in pumping the contents to 5 feet above is given as:

W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy

Plug in all the values. This gives,

W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

7 0
3 years ago
-2 - 6
Tatiana [17]

Answer:

-8

4

-15

-8

7

42

-60

15

-9

-12

Step-by-step explanation:

-2 - 6 = -8

8 + (-4) = 4

10 + (-25) = -15

-15 - (-7) = -8

-6 - (-13) = 7

-7 x -6 = 42

-12 x 5 = -60

60/4 = 15

72/-8 = -9

48/-4 = -12

6 0
3 years ago
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