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Anit [1.1K]
3 years ago
7

you have 5 red crayons, 3 yellow crayons, 4 blue crayons and purple crayons. what multiplication would you do to find the probab

ility of picking a blue then a red crayon.
Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

3/46

Step-by-step explanation:

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Find the area of the shaded region to the nearest tenth. See picture for full problem. Please and thank you so very much!
Romashka [77]

Answer:

66.3 sq ft

Step-by-step explanation:

Here's the plan: we'll find the area of the circle then subtract the area of the triangle.

Area of circle:

A = pi•r^2

= pi•6^2

= 3.14•36

~= 113.04

Area of triangle:

A = 1/2bh

= 1/2(10.39)(9)

The height is the 6+3 in the image.

~= 46.755

Subtract to find

Area of Shaded:

113.04 - 46.755

= 66.285

Round to nearest tenth.

~= 66.3 sq ft

8 0
3 years ago
Round 977.259856871 to 3 decimal places
Fofino [41]
You will want to round to 977.259

look at the number to the right of 9, it is 8, and 8 > 5. IF the number is 5 or greater, round up.

so your answer is 977.260

hope this helps
5 0
3 years ago
Read 2 more answers
HELP URGENT DUE IN 5 MINUTES URGENT PLEASE
VARVARA [1.3K]
The answer is C

x - 2y = 4
-x -x
-2y = 4 - x (divide that by 2)

Y = 1/2x - 2
4 0
3 years ago
Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert
Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

                        s=ut+\frac{1}{2} at^{2}

Here, s = distance of the balloon above the ground = - 80 feet

          u = intital velocity = 16 feet per second

          a = acceleration of the object = -32 feet per second

          t = required time

So,  s=ut+\frac{1}{2} at^{2}

      -80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})

       -80=16t-16 t^{2}

       16 t^{2} -16t -80 =0

          t^{2} -t -5 =0

Now, we will use the quadratic D formula for finding the value of t, i.e;

           t = \frac{-b\pm \sqrt{D } }{2a}

Here, a = 1, b = -1, and c = -5

Also, D = b^{2} -4ac = (-1)^{2} -(4 \times 1 \times -5) = 21

So,  t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}

      t = \frac{1\pm \sqrt{21 } }{2}

We will neglect the negative value of t as time can't be negative, so;

t = \frac{1+ \sqrt{21 } }{2} = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

                       v=u+at

Here, v = final velocity

So,  v=16+(-32 \times 2.79)

      v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

8 0
3 years ago
Can someone help please I need this asap
son4ous [18]

Answer:

<u>PART:A</u>

10_P_4=5040

<u>PART:B</u>

6_C_2=15

<u>PART:C</u>

6_C_2=15

Step-by-step explanation:

<u>PART:A</u>

When the four officers  are chosen than the number of ways of doing this is:

10_P_4

since we have to choose 4 officers and also they need to be arranged according to their ranks.

Hence, the numbers of ways doing so is:

10_P_4=\dfrac{10!}{(10-4)!}\\\\=\dfrac{10!}{6!}\\\\=10\times 9\times 8\times 7\\\\=5040

<u>PART:B</u>

Now we have to choose 2 members out of the remaining 6 members so the we have to use combination since we have to just choose the members and do not have to rank them or in short we can say we do not have to arrange them.

Hence, the number of ways doing this is:

6_C_2=\dfrac{6!}{2!\times (6-2)!}\\\\=\dfrac{6!}{2!\times 4!}\\\\=15

Hence, the number of ways of doing this is: 15.

<u>PART:C</u>

Now this process of doing so is also same as the above.

Hence, the number of ways of doing so is: 15.

8 0
3 years ago
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