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wolverine [178]
3 years ago
5

2 (5y-4)>32 Solve the inequality for y.

Mathematics
2 answers:
scoray [572]3 years ago
5 0

Answer:

y > 4

Step-by-step explanation:

2 (5y-4)>32

Divide each side by 2

2/2 (5y-4)>32/2

5y-4 > 16

Add 4 to each side

5y-4+4 > 16+4

5y > 20

Divide each side by 5

5y/5 > 20/5

y > 4

yan [13]3 years ago
4 0

Step-by-step explanation:

2 (5y - 4) > 32

10y - 8 > 32 (by expanding)

10y> 32 + 8

10y> 40

Y > 40/10

Y=4

Hope this helps..

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MatroZZZ [7]
X+52=149 x=97 hope this helped!
3 0
3 years ago
20 less than a number
agasfer [191]

Answer:

20 less than a number is equal to the number.

Step-by-step explanation:

8 0
3 years ago
4 1/3 - 1 2/3 how to solve this please
8_murik_8 [283]

Answer:

2\frac{2}{3}

Step-by-step explanation:

1) Convert 4\frac{1}{3} to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{4\times3+1}{3} -1\frac{2}{3}

2) Simplify 4 * 3 to 12.

\frac{12+1}{3}

3) Simplify 12 + 1 to 13.

\frac{13}{3} -1\frac{2}{3}

4) Convert 1\frac{2}{3}   to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{13}{3} -\frac{1\times3+2}{3}

5) Simplify 1 * 3 to 3.

\frac{13}{3} -\frac{3+2}{3}

6) Simplify 3 + 2 to 5.

\frac{13}{3} -\frac{5}{3}

7) Join the denominators.

\frac{13-5}{3}

8) Simplify.

\frac{8}{3}

9) Convert to mixed fraction.

2\frac{2}{3}

(Decimal Form: 2.666667)

Thank you,
Eddie

3 0
2 years ago
. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)
charle [14.2K]

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

           2 sqrt(2x-1)

5 0
3 years ago
Read 2 more answers
A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter
Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

x+y=15\operatorname{cm}

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}

We can now refine the equation as follow;

\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}

ANSWER:

The length of the shorter piece of wire is 6cm

7 0
1 year ago
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