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melomori [17]
3 years ago
7

A rectangle has perimeter 20m. Express the area of the rectangle as a function of the length of one of its sides.

Mathematics
1 answer:
MArishka [77]3 years ago
7 0
<h2>Area of rectangle is 10L-L²</h2>

Step-by-step explanation:

Let L be the length and W be the width.

Perimeter of rectangle = 2 ( L + W )

That is

           2 ( L + W ) = 20

               L + W = 10

                     W = 10 - L

We need to express the area of the rectangle as a function of the length of one of its sides.

           Area = Length x Width

              A = LW

               A = L(10 - L) = 10L-L²

Area of rectangle is 10L-L²

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15 Points!<br> Find the range of the functions:<br><br> f(x) = (x + 1)^2 - 1<br><br> f(x) = 7x - 11
MakcuM [25]

In both cases you may well benefit from graphing the functions.

Do you recognize f(x) = (x + 1)^2 - 1 as a quadratic function, whose graph is that of a parabola that opens up? By comparing this to y = a(x-h)^2 + k, we see that a=1, h= -1 and k = -1. The vertex is at (h,k), which here is the point (-1, -1). This is the minimum value of the function. Thus, the range of this function is [-1, infinity).


Now for the function f(x) = 7x - 11: This is a linear function whose graph is (surprise!) a straight line. When x increases, y increases, without limits to either. Similarly, when x decreases, y decreases.

Thus the range includes all real numbers: (-infinity, infinity).

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3 years ago
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Alisiya [41]
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n200080 [17]

1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

<u>Step-by-step explanation</u>:

The general form of quadratic equation is ax²+bx+c = 0

where

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

<u>To find the roots :</u>

  • Sum of the roots = b
  • Product of the roots = c

1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

  • Sum of the roots = -7+2 = -5
  • Product of the roots = -7\times2 = -14

The solution is given by (x-7) (x+2) = 0.

Therefore, the solutions are x=7 and x= -2.

2) The given quadratic equation is b² - 4b + 4 = 0.

From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

  • Sum of the roots = -2-2 = -4
  • Product of the roots = -2\times-2 = 4

The solution is given by (x-2) (x-2) = 0.

Therefore, the solution is x=2.

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Answer:

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Step-by-step explanation:

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