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fredd [130]
3 years ago
11

Which of the following are required for an independent random sample? Check all that apply. Every time an individual is selected

for the sample, each of the remaining individuals has a lower chance of being included. The probability of being included in the sample is the same for all members of the population of interest. The probability of being selected first for the sample is the same as the probability of being selected last. Every time an individual is selected for the sample, each of the remaining individuals has a higher chance of being included.
Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

the probability of being included in the sample is same for all members of the population of interest. the probability of being selected first for the sample is same as the probability of being selected last

Step-by-step explanation:

A sample is said to be independent random sample if each member of the population has equal chance of being selected.

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If my assignment is worth 14% of my quiz weight which is 27% of my total weight what is the weight of that assignment
Nimfa-mama [501]

Answer:

3.785%

Step-by-step explanation:

Assignment is 14% of the quiz

=> Assignment = 14% of the quiz

Quiz is 27% of the total weightage

=> 14% of 27%

<u>Find 14% of 27% </u>

14% of 27%

= 0.14 x 27 = 3.785%

The assignment is 3.785% of the total weightage.

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3) 0.0612

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365 x 87

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A distributor needs to mix some Terraza coffee that normally sells for $9.00 per pound with some Kona coffee that normally sells
Scrat [10]

Answer:

Step-by-step explanation:

Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:

                #lbs     x       $/lb       =         Total

T

K

Mix

Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:

                 #lbs        x        $/lb       =        Total

T                                           9

K                                         13.50

Mix

Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound

                  #lbs      x       $/lb        =        Total

T                                         9

K                                       13.50

Mix              50                 9.54

Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:

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T                   x        x          9         =        9x

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Mix            50        x         9.54     =     477

The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:

9x + 675 - 13.5x = 477 and

-4.5x = -198 so

x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.

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