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yuradex [85]
3 years ago
15

If my assignment is worth 14% of my quiz weight which is 27% of my total weight what is the weight of that assignment

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

3.785%

Step-by-step explanation:

Assignment is 14% of the quiz

=> Assignment = 14% of the quiz

Quiz is 27% of the total weightage

=> 14% of 27%

<u>Find 14% of 27% </u>

14% of 27%

= 0.14 x 27 = 3.785%

The assignment is 3.785% of the total weightage.

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Help me with these math questions....
Nady [450]

Answer: cotθ

<u>Step-by-step explanation:</u>

 tanθ * cos²θ * csc²θ

=  \dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}

= \dfrac{cos\theta}{sin\theta}

= cotθ

Answer: B

<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

  • reflection over the x-axis
  • vertical shift up 3 units

Answers:

  • a. Quadrant II
  • b. negative
  • c. \dfrac{\pi}{6}
  • d. C
  • e.-\dfrac{\sqrt{3}}{3}

<u>Explanation:</u>

\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}

a) Quadrant 2 is: \dfrac{\pi}{2} < \theta < \pi

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) \pi-\dfrac{5\pi}{6} = \dfrac{\pi}{6}

d) the reference line is above the x-axis so it is negative -->  -tan\dfrac{\pi}{6}

e) tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}


4 0
2 years ago
HELP ME! I can't estimate!
klasskru [66]

Answer: -144.1226

Step-by-step explanation:

4 0
2 years ago
The radius of circle B is 6 centimeters. The area of the shaded sector is 31.42 square centimeters. Calculate the angle of the s
algol13

Answer:

100

Step-by-step explanation:

i dont know but the website i was on said 100

5 0
3 years ago
What is the answer to this? −1.3≥2.9−0.6r
Karolina [17]

Answer:

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

Step-by-step explanation:

−1.3 ≥ 2.9 − 0.6r

Rewrite so r is on the left side of the inequality.

2.9 − 0.6r  ≤ −1.3

Move all terms not containing r to the right side of the inequality.  

Subtract 2.9 from both sides of the inequality.

−0.6r  ≤ −1.3 − 2.9

Subtract 2.9 from −1.3.

−0.6r  ≤ −4.2

Divide each term by −0.6 and simplify.

      Divide each  term in −0.6r  ≤ −4.2 by −0.6. When multiplying or dividing both sides of an

      inequality by a negative value, f lip the direction of the inequality sign.

       −0.6r /−0.6 ≥  −4.2 /−0.6

       Cancel the common factor of −0.6.

                  −4.2

          r ≥    ______

                  −0.6

 Divide −4.2 by −0.6.

r ≥ 7

The result can be shown in multiple forms.

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

6 0
3 years ago
Solve for d when 2x-2yd=y+xd ...?
11Alexandr11 [23.1K]
2x-2yd=y+xd 2x-y=xd+2yd 2x-y=d(x+2y) (2x-y)/(x+2y)=d So the answer is <span><span>d=<span><span>2x−y</span><span>x+2y</span></span></span></span>
3 0
3 years ago
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