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Colt1911 [192]
3 years ago
5

X 10/10=18/12 solve for x

Mathematics
1 answer:
just olya [345]3 years ago
8 0
Simplifying: x+1=18/12

Simplify: x+1=1.5

Combine Like Terms: 1x=1.5-1

Simplify: 1x=0.5

Divide: x=0.5


Hope I helped :)
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Simplify the expression: 7 - 7(5 + x) - 9x <br> Your answer
Gekata [30.6K]

Answer:

-16x-28

Step-by-step explanation:

Break it into little pieces; start with distributing the -7:

-7(5+x)

-35-7x

Now add the rest of the problem: 7-35-7x-9x

Combine like terms: 7-35               7x-9x

7-35=-28             7x-9x=-16x

Rearrange so the coefficient and variable are upfront, giving you:

-16x-28

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3 years ago
A polygon is regular if each of its sides has the same length. Find the perimeter of the regular polygon. #36
vazorg [7]
Take the length of one of the sides and times that by the radius. Divide that answer by 2. Now take that and multiply by the number of sides the polygon has. If you can't find the radius or side, you're going to have to use tan, sin, or cos.
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A farmer knows that a crop she is growing requires 24 kg of fertilizer throughout the season. She has a measuring flask which wh
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Answer:

48 times

Step-by-step explanation:

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8 0
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A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
72.6 meters in 11 seconds
ira [324]
This would simplify to 6.60 meters/second.
8 0
3 years ago
Read 2 more answers
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