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3 years ago

Need Help on this ASAP Geometry

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

You calculate it by taking the change in y's over the change in x's. So (y1-y2)/(x1-x2). You get the equation (-5 - 3)/(5 - 7) which equals 4. 4 is the slope.

Arada [10]3 years ago

3 0

Distance Between 2 Points = Sqr Root [(X2 -X1)^2 + (Y2 -Y1)^2]Distance= Sqr Root [(7 -5)^2 + (3 --5)^2]Distance= Sqr Root [ 4 + 64 ]Distance= Sqr Root [ 68 ] Distance= 8.2462112512 
Source:http://www.1728.org/distance.htm

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HELP ASAP!! HELP FAST!!

erma4kov [3.2K]

The perfect square is answer A

8 0

2 years ago

What’s the answer? And why

lbvjy [14]

B; if P equals one they would ha. have to divided it by 10 so do that to 4.3 and you would get 0.43

4 0

3 years ago

NECESITO AYUDA EN ESTOS EJERCIICIOS DE MATES NIVEL SEGUNDO ESO

Kay [80]

Answer: 49/60

Step-by-step explanation:

(1/3+2/5)-1/4-(5/6-7/6)

Primero (5/6-7/6)

5/6-7/6=-2/6

1/3+2/5-1/4-(-2/6)

1/3+2/5-1/4+2/6

2/6=1/3

1/3+2/5-1/4+1/3

2/3+2/5-1/4

2/3=10/15

2/5=6/15

10/15+6/15-1/4

16/15-1/4

16/15=64/60

1/4=15/60

64/60-15/60=49/60

4 0

3 years ago

Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

2 years ago

Hey all you math geniuses can you help me with this question that should be easy

kenny6666 [7]

Answer:

(B) $\frac{-3}{x}$

Step-by-step explanation:

A polynomial is the expression which consists of addition, subtraction, multiplication with any variables or constants but the division with a variable is not considered as a polynomial.

Since $\frac{-3}{x}$ consists of division of -3 with a variable, therefore it is not a polynomial, rest all other options are polynomial as they involve addition,multiplication with variables.

7 0

3 years ago