Question

Which is the graph of g(x) = (0.5)x + 3 – 4? On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, negative 4). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 3. It crosses the y-axis at (0, 3). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, 4). On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 4. It crosses the y-axis at (0, 12).

Answer 1

Answer: The correct answer is A.

i just did the quiz and put C but it is incorrect

hope this helps you :)

Answer 2

Answer:

The graph will be an exponential function that crosses the y-axis at about (0, -4).

Step-by-step explanation:

$g(x) = (0.5)^{x + 3} - 4$

That means that when x = 0...

$g(0) = (0.5)^{0 + 3} - 4$

$g(0) = (0.5)^{3} - 4$

$g(0) = 0.125 - 4$

$g(0) = -3.875$

So, the graph will be an exponential function that crosses the y-axis at about (0, -4).

Hope this helps!