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Allisa [31]
2 years ago
13

Average Weekly Earnings The average weeklyearnings in dollars for various industries are listedbelow. Find the percentile rank o

f each value.
804 736 659 489 777 623 597 524 228
For the same data, what value corresponds to the 40th percentile
Mathematics
1 answer:
salantis [7]2 years ago
3 0

Answer:

a. 228- 6th, 489- 17th, 524- 28th, 597- 39th, 623- 50th, 659- 61th, 736- 72th, 777- 83th, 804- 94th

b. 597

Step-by-step explanation:

arrange the data:

228, 489, 524, 597, 623, 659, 736, 777, 804

a. percentile = ((number of items below position + 0.5)/ number of items ) 100

for 228 = (0+0.5/ 9) 100 = 6th

for 489 = (1+0.5/ 9) 100 = 17th

for 524 = (2+0.5/ 9) 100 = 28th

for 597 = (3+0.5/ 9) 100 = 39th

for 623 = (4+0.5/ 9) 100 = 50th

for 659 = (5+0.5/ 9) 100 = 61th

for 736 = (6+0.5/ 9) 100 = 72th

for 777 = (7+0.5/ 9) 100 = 83th

for 804 = (8+0.5/ 9) 100 = 94th

b. The corresponding value for the 40th = number of item( percentile)/ 100

   = 9( 40) / 100 = 3.6 approximately 4th which is 597

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The value of x in the proportion is x = 39/8

<h3>How to solve the proportion?</h3>

The proportion is given as:

3/8 =x/13

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Divide by 8

x = 39/8

Hence, the value of x in the proportion is x = 39/8

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Answer:

y = 4x - 12

Step-by-step explanation:

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with (x₁, y₁ ) = E(4, 4) and (x₂, y₂ ) = F(2, - 4)

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Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

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The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

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The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

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The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

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