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Lesechka [4]
3 years ago
11

In the poportion 1/z =4/5/8 which number is equal to z in the proportion

Mathematics
1 answer:
Nady [450]3 years ago
8 0

Answer:

case 1) z=10

case 2) z=5/32

Step-by-step explanation:

case 1) we know that

Using proportion

\frac{1}{z}=\frac{(4/5)}{8}

solve for z

\frac{1}{z}=\frac{(4/5)}{8}\\ \\z(4/5)=8\\ \\z=8*5/4\\ \\z=10

case 2) we know that

Using proportion

\frac{1}{z}=\frac{4}{5/8}

solve for z

\frac{1}{z}=\frac{4}{5/8}\\ \\4z=5/8\\ \\z=5/32

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In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value.
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Identify the zeros of the function f(x) = 2x^2 − 4x + 5 using the Quadratic Formula
Nostrana [21]

For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.

Then, we must find the roots of:

2x ^ 2-4x + 5 = 0

Where:

a = 2\\b = -4\\c = 5

We have to:x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Substituting we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (2) (5)}} {2 (2)}\\x = \frac {4 \pm \sqrt {16-40}} {4}\\x = \frac {4 \pm \sqrt {-24}} {4}

By definition we have to:

i ^ 2 = -1

So:

x = \frac {4 \pm \sqrt {24i ^ 2}} {4}\\x = \frac {4 \pm i \sqrt {24}} {4}\\x = \frac {4 \pm i \sqrt {2 ^ 2 * 6}} {4}\\x = \frac {4 \pm 2i \sqrt {6}} {4}\\x = \frac {2 \pm i \sqrt {6}} {2}

Thus, we have two roots:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

Answer:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

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3 years ago
12 out of 20 doctors agree 15 out of 30 doctors agree are the ratios equivalent
uysha [10]
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4 0
3 years ago
PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.
Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}

Thus, the equation will be of the form:

y-y_ {0} = - \frac {1} {4} (x-x_ {0})

Finally we substitute the given point and we have:

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Answer:

Option B

8 0
3 years ago
Trapezia ABCD and PQRS are similar.<br> Find the area shaded in green.
avanturin [10]

The area shaded in green is 864 cm²

<h3>Similar figures</h3>

Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,

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RS = 240 / 30

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let find the height of trapezium PQRS.

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30h = 360

h = 360 / 30

h = 12 cm

Therefore,

area of the green portion = area of ABCD - area of PQRS

<h3>Area of a trapezium</h3>
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Therefore,

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area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²

Area of the green portion = 972 - 108 = 864 cm²

learn more on trapezium here: brainly.com/question/11961445

6 0
2 years ago
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