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Anit [1.1K]
3 years ago
13

IOS 0R ANDR0ID ???

Computers and Technology
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

Both are awesome!

Explanation:

One thing we shouldn't do is downgrade others for having an android or calling someone basic because they have ios. Both have their pros and cons, but idk because I don't have a phone! Hehe. But my family primarily uses IOS.

You might be interested in
Write the proghrams for the following:
belka [17]

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

5 0
3 years ago
HELP 99PTS If Answered
Alborosie

You will have to do this as we are not you and we do not know local business/websites. Sorry we could not help.

3 0
3 years ago
Read 2 more answers
Use an ifstream object named indata to read the first three integers from a file called lottowins and write each number to stand
Gemiola [76]

Answer:

int x;

indata.open("lottowins");

indata >> x;

cout << x << endl;

indata >> x;

cout << x << endl;

indata >> x;

cout << x << endl;

indata.close();

4 0
3 years ago
Implement a sublinear running time complexity recursive function in Java public static long exponentiation (long x, int n) to ca
Archy [21]

Answer:

Following are the code block in the Java Programming Language.

//define recursive function

public static long exponentiation(long x, int n) {

//check the integer variable is equal to the 0.

if (x == 0) {

//then, return 1

return 1;

}

//Otherwise, set else

else {

//set long data type variable

long q = exponentiation(x, n/2);

q *= q;

//check if the remainder is 1

if (n % 2 == 1) {

q *= x;

}

//return the variable

return q;

}

}

Explanation:

<u>Following are the description of the code block</u>.

  • Firstly, we define the long data type recursive function.
  • Then, set the if conditional statement and return the value 1.
  • Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
  • Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
8 0
3 years ago
Write a program that can be used to assign seats for a commercial airplane. The airplane has 13 rows, with six seats in each row
d1i1m1o1n [39]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

#include <stdio.h>

#include <cst dlib>

using namespace st d;

int main(int argc, char *argv[])

{

int airplane[13][6];

char airchar[13][6];

string ticket;

int row[2];

char seat;

//--------------------------------------------

for(int i = 0; i < 13; i++)

{

for(int j = 0; j < 6; j++)

{

airchar[i][j] = '*';

airplane[i][j] = 0;

}

}

//--------------------------------------------

for(;;)

{

cout<<"Rows 1 and 2 are first class (F C)"<<endl;

cout<<"Rows 3 through 7 are business class (B C)"<<endl;

cout<<"Rows 8 through 13 are economy class (E C)"<<endl;

cout<<endl;

cout<<"* - Available"<<endl;

cout<<"X - Occupied"<<endl;

cout<<endl;

cout<<" \t A\t B\t C\t D\t E\t F"<<endl;

cout<<"Row 1\t"<<airchar[0][0]<<"\t"<<airchar[0][1]<<"\t"

<<airchar[0][2]<<"\t"<<airchar[0][3]<<"\t"<<airchar[0][4]<<"\t"

<<airchar[0][5]<<endl;

cout<<"Row 2\t"<<airchar[1][0]<<"\t"<<airchar[1][1]<<"\t"

<<airchar[1][2]<<"\t"<<airchar[1][3]<<"\t"<<airchar[1][4]<<"\t"

<<airchar[1][5]<<endl;

cout<<"Row 3\t"<<airchar[2][0]<<"\t"<<airchar[2][1]<<"\t"

<<airchar[2][2]<<"\t"<<airchar[2][3]<<"\t"<<airchar[2][4]<<"\t"

<<airchar[2][5]<<endl;

cout<<"Row 4\t"<<airchar[3][0]<<"\t"<<airchar[3][1]<<"\t"

<<airchar[3][2]<<"\t"<<airchar[3][3]<<"\t"<<airchar[3][4]<<"\t"

<<airchar[3][5]<<endl;

cout<<"Row 5\t"<<airchar[4][0]<<"\t"<<airchar[4][1]<<"\t"

<<airchar[4][2]<<"\t"<<airchar[4][3]<<"\t"<<airchar[4][4]<<"\t"

<<airchar[4][5]<<endl;

cout<<"Row 6\t"<<airchar[5][0]<<"\t"<<airchar[5][1]<<"\t"

<<airchar[5][2]<<"\t"<<airchar[5][3]<<"\t"<<airchar[5][4]<<"\t"

<<airchar[5][5]<<endl;

cout<<"Row 7\t"<<airchar[6][0]<<"\t"<<airchar[6][1]<<"\t"

<<airchar[6][2]<<"\t"<<airchar[6][3]<<"\t"<<airchar[6][4]<<"\t"

<<airchar[6][5]<<endl;

cout<<"Row 8\t"<<airchar[7][0]<<"\t"<<airchar[7][1]<<"\t"

<<airchar[7][2]<<"\t"<<airchar[7][3]<<"\t"<<airchar[7][4]<<"\t"

<<airchar[7][5]<<endl;

cout<<"Row 9\t"<<airchar[8][0]<<"\t"<<airchar[8][1]<<"\t"

<<airchar[8][2]<<"\t"<<airchar[8][3]<<"\t"<<airchar[8][4]<<"\t"

<<airchar[8][5]<<endl;

cout<<"Row 10\t"<<airchar[9][0]<<"\t"<<airchar[9][1]<<"\t"

<<airchar[9][2]<<"\t"<<airchar[9][3]<<"\t"<<airchar[9][4]<<"\t"

<<airchar[9][5]<<endl;

cout<<"Row 11\t"<<airchar[10][0]<<"\t"<<airchar[10][1]<<"\t"

<<airchar[10][2]<<"\t"<<airchar[10][3]<<"\t"<<airchar[10][4]<<"\t"

<<airchar[10][5]<<endl;

cout<<"Row 12\t"<<airchar[11][0]<<"\t"<<airchar[11][1]<<"\t"

<<airchar[11][2]<<"\t"<<airchar[11][3]<<"\t"<<airchar[11][4]<<"\t"

<<airchar[11][5]<<endl;

cout<<"Row 13\t"<<airchar[12][0]<<"\t"<<airchar[12][1]<<"\t"

<<airchar[12][2]<<"\t"<<airchar[12][3]<<"\t"<<airchar[12][4]<<"\t"

<<airchar[12][5]<<endl;

cout<<endl;

cout<<"Enter Ticket type (F C, B C, or E C): ";

cin>>ticket;

cout<<"Desired Row: ";

cin>>row[0];

cout<<"Desired seat (A,B,C,D,E or F): ";

cin>>seat;

switch(seat)

{

case 'A':

case 'a':

row[0] = row[0] - 1;

row[1] = 1;

row[1] = row[1] - 1;

break;

case 'B':

case 'b':

row[0] = row[0] - 1;

row[1] = 2;

row[1] = row[1] - 1;

break;

case 'C':

case 'c':

row[0] = row[0] - 1;

row[1] = 3;

row[1] = row[1] - 1;

break;

case 'D':

case 'd':

row[0] = row[0] - 1;

row[1] = 4;

row[1] = row[1] - 1;

break;

case 'E':

case 'e':

row[0] = row[0] - 1;

row[1] = 5;

row[1] = row[1] - 1;

break;

case 'F':

case 'f':

row[0] = row[0] - 1;

row[1] = 6;

row[1] = row[1] - 1;

break;

}

if(ticket == "F C")

{

if(row[0]+1 == 1 || row[0]+1 == 2)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "B C")

{

if(row[0]+1 == 3 || row[0]+1 == 4 || row[0]+1 == 5

|| row[0]+1 == 6|| row[0]+1 == 7)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "E C")

{

if(row[0]+1 == 8 || row[0]+1 == 9 || row[0]+1 == 10

|| row[0]+1 == 11|| row[0]+1 == 12|| row[0]+1 == 13)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

row[0] = 0;

row[1] = 0;

system("cls");

}

return 0;

}

6 0
3 years ago
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