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PolarNik [594]
3 years ago
7

What are three reasons teens might start drinking alcohol??

Computers and Technology
2 answers:
vampirchik [111]3 years ago
3 0
1. Social Media Influence (ex; influence by videos on snapchat, youtube or Tv)

2. Peer pressure (but that mostly falls into the same category as 1), so another reason could be "Teenage rebellion" in todays society we see everywhere that it is expected for teens to act up and experience things such as underage
drinking. 

3. Influence at home! Believe it or not a lot of parents will allow their teens to drink at home and/or invite their friends over and provide them alcohol because "they rather have the teens do it at their house than the kids hiding that from the parents" <span />
gavmur [86]3 years ago
3 0
There are many reasons why teens might start drinking alcohol. every teen different so each person has there own reasons. One reason could be peer pressure every teen is trying to fit in or trying to be cool so when they see their friends and classmates drinking they want to fit in and if they reject students will usually laugh at them or bully them.

Another reason could be self-medication. teens go through daily struggles and can't talk about their personal issues so they try to find another way to escape this isn't just for teens many adults do this. Also many teens suffer depression and anxiety so they drink to numb the pain or at least ease the pain.

The third reason could  be rebellion. teens love going against their parents especially during there teens years and they feel like they know everything and they think they know whats best so when strict parents tell them do anything they will do the exact opposite. Lastly  so teens might just love to party and might just drink for fun and some might get addicted to alcohol and can't stop drinking. 

Hope this helps

can you please make this the brainiest question 

Thank you :)

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#Write a function called find_median. find_median #should take as input a string representing a filename. #The file correspondin
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Answer:

Explanation:

The following is written in Python. It takes in a file, it then reads all of the elements in the file and adds them to a list called myList. Then it sorts the list and uses the elements in that list to calculate the median. Once the median is calculated it returns it to the user. The code has been tested and the output can be seen in the image below.

def find_median(file):

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   mylist = []

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Answer:

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit  memory  to add in 2 location:

\to \frac{0}{1}  =2^1  \ (\frac{m}{m}  \ location)

The address of 2-bit  memory to add in 4 location:

\to \frac{\frac{00}{01}}{\frac{10}{11}}  =2^2  \ (\frac{m}{m}  \ location)

similarly,

Complete 'n'-bit memory address' location number is = 2^n.Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

= 2^n \\\\ = 2^{12} \\\\ = 4096

In point b:

\to Let \  Mega= 10^6

              =10^3\times 10^3\\\\= 2^{10} \times 2^{10}

So,

\to 2 \ Mega =2 \times 2^{20}

                 = 2^1 \times 2^{20}\\\\= 2^{21}

The memory position for '2^n' could be 'n' m bits'  

It can use 2^{21} bits to address the memory location of 21.  

That is to say, the 2-mega-location memory needs '21' bits.  

Memory Length = 21 bit Address

In point c:

i^{th} element array addresses are given by:

\to address [i] = B+w \times (i-LB)

_{where}, \\\\B = \text {Base  address}\\w= \text{size of the element}\\L B = \text{lower array bound}

\to B=\$ 52\\\to w= 4 byte\\ \to L B= 0\\\to address  = 10

\to address  [10] = \$ 52 + 4 \times (10-0)\\

                       =   \$ 52   + 40 \ bytes\\

1 term is 4 bytes in 'MIPS,' that is:

= \$ 52  + 10 \ words\\\\ = \$ 512

In point d:

\to  base \ address = \$ t 5

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are  < 4 byte

Calculating address:

\to address  [5] = \$ t5 + 4 \times (5-0)\\

                     = \$ t5 + 4 \times 5\\ \\ = \$ t5 + 20 \\\\= \$ t5 + 20  \ bytes  \\\\= \$ t5 + 5 \ words  \\\\= \$ t 10  \ words  \\\\

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