Answer:
He forgot to give credit to the sources at the end.
If you take something from a different source and you quote it, you must give credit at the end or it can go down as plagiarism.
Data items are "local".
Consider the following example in C++.
class MyClass
{
public:
void setX(int x)
{
this->x = x;
}
private:
int x;
};
We have an integer variable local to the scope of the class declaration, and we have another integer variable local to our setX() function, though we have no global functions, that's something you want to try to avoid as a general rule of thumb.
Answer:
Check the explanation
Explanation:
#include <stdio.h>
int inversions(int a[], int low, int high)
{
int mid= (high+low)/2;
if(low>=high)return 0 ;
else
{
int l= inversions(a,low,mid);
int r=inversions(a,mid+1,high);
int total= 0 ;
for(int i = low;i<=mid;i++)
{
for(int j=mid+1;j<=high;j++)
if(a[i]>a[j])total++;
}
return total+ l+r ;
}
}
int main() {
int a[]={5,4,3,2,1};
printf("%d",inversions(a,0,4));
return 0;
}
Check the output in the below attached image.
Answer:
open source software
Explanation:
A software that is free and whose code can be accessed and potentially modified by anyone is referred to as an open source software. The license used by the developer of an open source software grants all users the permission to use, distribute and modify the software at any time.
Some examples of an open source software are Firefox, gimp, OpenOffice etc.
Answer:
Check the explanation
Explanation:
MATLAB code:
%----------------------
function result = dominant(A)
% matrix dimensions
d = size(A);
% for loop over rows
for i = 1:d
% sum of row elements except diagonal element
sum_row =0;
% for loop over columns
for j = 1:d
% adding each elements to sum variable
sum_row = sum_row+ abs(A(i,j));
end
%subratcting diagonal element
sum_row = sum_row-abs(A(i,i));
%checking dominant condition
% failed once means matrix is not diagonal dominant
if abs(A(i,i))< sum_row
result = 'false';
return;
end
end
% dominant condition not failed
result = 'true';
end
% matrix A
A = [ 3 -2 1; 1 -3 2; 1 2 6]
% result
result = dominant(A)
% matrix A
A = [ -2 1 2; 1 3 2; 1 -2 0]
% result
result = dominant(A)
%----------------------
Kindly check the attached output image below.