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kvasek [131]
3 years ago
7

Let n = the number. A number exceeds 45 inequality

Mathematics
1 answer:
blondinia [14]3 years ago
3 0
  This translates to "a number" is greater than 45. All you have to do now is translate these words into an algebraic statement. Basically, you replace "a number" with the variable which it is defined for, and you use the "greater than" symbol to show that the variable is greater than the value of 45.
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melisa1 [442]

Answer:

For the 99th percentile, we have X = 206 seconds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 138.5, \sigma = 29

99th percentile:

Value of X when Z has a pvalue of 0.99. So we use Z = 2.325

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 138.5}{29}

X - 138.5 = 29*2.325

X = 205.92 = 206

For the 99th percentile, we have X = 206 seconds.

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