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Elena-2011 [213]
3 years ago
5

Please answer this question full

Mathematics
1 answer:
ira [324]3 years ago
7 0
(5x-2) + (2x+6) = 67, so we simplify and solve for x:
7x + 4 = 67 --> 7x = 63 --> x = 9

Now we substitute 9 for x in (5x-2):
5(9) - 2 --> 45 - 2 = 43

The distance between A and B is 43 miles.
Hope this Helps!
Brainliest Please!
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Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m?
SpyIntel [72]
The answer would be m^2+3m+2=0 because the first “part” of the equation (x^2-5) is equal to m; in the equation it’s squared so it can be replaced by m^2. next, 3m is the same as 3(x^2+5) which is what you have when you see 3x^2+15. finally, you have to bring the -2 over from the other side so you have positive 2. hope this helps!
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3 years ago
Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric
quester [9]
I'm guessing S^20 is actually referring to the 20th partial sum S_{20}, with

S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)

in the arithmetic case, and

S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}

in the geometric case.

(a) Combining like terms, we have

S_{20}=20+0.1(1+2+\cdots+18+19)

and invoking the formula

1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2

we end up with

S_{20}=20+0.1\dfrac{19\times20}2=39

(b) Multiply S_{20} by 1.1, then subtract this from S_{20}:

1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}

S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}
\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275
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3 years ago
Eden find this and help me
FromTheMoon [43]

Answer:

HELP PLS

Step-by-step explanation:

brainly.com/question/20139113

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2 years ago
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How many time does 8 go into 27
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It is: 27/8 = 3 with a remainder of 3


4 0
3 years ago
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I don't understand (t+8)(-2)=12
Evgen [1.6K]
It it called an equation. Equation consist of number, symbols, and a equal sign.
To solve, first do -2 times t and -2 times 8. Your equation would look like this after: -2T+(-16)=12. Then add 16 to each side. -2T=28. Next, divide by -2. T=-14 is your answer.
5 0
2 years ago
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