Equally distant is the answer, I believe. Because absolute value is the same whether it's negative or positive. So they would be equally distant
<h2>Andrew is incorrect </h2>
because 2^28 = 268,435,456
<h2>follow me</h2>
Answer:
See explanation
Step-by-step explanation:
<u>Given:</u> ΔABC ≅ ΔDEF
AM, DN - medians
<u>Prove:</u> AM ≅ DN
Proof:
1. Congruent triangles ABC and DEF have congruent corresponding parts:
- AB ≅ DE;
- BC ≅ EF;
- ∠ABC ≅ ∠DEF.
2. BM ≅ MC - definition of the median AM;
3. EN ≅ NF - definition of the median DN;
4. AB ≅ 2BM, EF ≅ 2EN
BM ≅ 1/2 AB,
EN ≅ 1/2 EF,
thus, BM ≅ EN
5. Consider two triangles ABM and DEN. In these triangles \:
- AB ≅ DE (see 1));
- BM ≅ EN (see 4));
- ∠ABM ≅ ∠DEN (see 1).
So, ΔABM ≅ ΔDEN by SAS postulate.
6. Congruent triangles ABM and DEN have congruent corresponding sides BM and DN.
Answer: B
Step-by-step explanation:
Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
