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2 years ago

IN

Mathematics

1 answer:

Masja [62]2 years ago

3 0

No hablo ni escribo inglés ponlo en español

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Tell me which statements belong in "agree" and disagree".

Delvig [45]

Answer:

Rig

Step-by-step explanation:

4 0

2 years ago

3. Find the value of a and b when<br>5+√6/5-√6 = a+b√6

mr Goodwill [35]

The answer for A is,

$a = 5 + \frac{ \sqrt{6} }{ \sqrt{5} } - \sqrt{6} - \sqrt{6b}$

And the answer for B is,

$b = - 1 + \frac{5 + \frac{ \sqrt{6} }{ \sqrt{5} } - a }{ \sqrt{6} }$

hope it helps.

sorry of its wrong.

4 0

3 years ago

Express this equation in logarithmic form. y = 10^x<br><br> x = ?

Lana71 [14]

From definition we have:

$$x=\log_{10}y$

8 0

2 years ago

Can someone tell me some word problems already solved? dividing and multiplying decimals and integers by 100,10 and 1000. I need

const2013 [10]

Answer:

wait im a little confused sorry but im going to try my best

Step-by-step explanation:

50x2=100. 5×2=10. 500x2=1,000

1,000÷10=100. 100÷10=10. 10,000÷10=1,000

5 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago