Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k
we have some points
(3,-2) and (6,-26)
input and solve for a and k
(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k
(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k
we have
-2=a+k
-26=4a+k
multiply first equation by -1 and add to second
2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k
-24=3a
divide both sides by 3
-8=a
-2=a+k
-2=-8+k
add 8 to both sides
6=k
the equation is
Answer:
-3
Step-by-step explanation:
goes up 3
goes back -1
3/-1
BREAKDOWN
10 times: 10 ×
The sum of: ( ) + ( )
which would be : 10 × ( ) + ( )
half a number: 10 × ( X/2 ) + ( )
and 8: 10 × ( X/2 ) + ( 8 )
is 12 : 10 × ( X/2 + 8 ) = 12
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SIMPLIFICATION
Multiply ten: 10 X (X/2 + 8) = 12
which equals to: 5x + 80 = 12
bring the like terms together: 5x = 80 - 12
Equals: 5x = 78
Find out X:. x = 78/5
FINAL ANSWER:. X = 15.9
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