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Anna11 [10]
3 years ago
9

Orange juice is _____. an acid a base a neutral

Chemistry
1 answer:
weqwewe [10]3 years ago
4 0
An acid because of its high content of citric acid
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The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
Aloiza [94]

Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
A compound is made of 6.00 grams of oxygen, 7.00 grams of nitrogen, and 20.00grams of hydrogen. Find the percent composition of
xxTIMURxx [149]

The percent composition of the compound.

A O-18.18%, N-21.21%, H-60.60%

<h3>Further explanation</h3>

Given

6.00 grams of oxygen,

7.00 grams of nitrogen,

20.00 grams of hydrogen.

Required

The percent composition

Solution

Total mass :

= mass of O + mass of N + mass of H

= 6 + 7 + 20

= 33 g

% O = 6/33 x 100%= 18.18%

% N = 7/33 x 100%=21.21%

% H = 20/33 x 100% = 60.6 %

6 0
3 years ago
Could someone help me with this question? Thank you
KonstantinChe [14]

VALENCE ELECTRONS DETERMINE CHEMICAL PROPERTIES BECAUSE WHEN SAME ELEMENT REACT WITH DIFFERENT ELEMENTS THEN DIFFERENT COMPOUNDS ARE FORMING.FOR EXAMPLE HYDROGEN BOND WITH OXYGEN THEY FORM WATER AND WHEN HYDROGEN BOND WITH CHLORINE THEY FORM HCL  WHICH SHOWS DIFFERENT PROPERTIES FROM WATER.

7 0
4 years ago
The iodide ion concentration in a solution may be determined by the precipitation of lead iodide. Pb2 (aq) 2I-(aq) PbI2(s) A stu
MatroZZZ [7]

Answer:

M_{I^-}=0.6841M

Explanation:

Hello.

In this case, since the precipitation of the lead iodide is related to the iodide ion in solution, if we make react lead (II) nitrate with an iodide-containing salt, a possible chemical reaction would be:

Pb(NO_3)_2+2I^-\rightarrow PbI_2+2NO_3^-

In such a way, since 15.71 mL of a 0.5770-M solution of lead (II) nitrate precipitates out lead (II) iodide, we can first compute the moles of lead (II) nitrate in the solution:

n_{Pb(NO_3)_2}=0.5570\frac{molPb(NO_3)_2}{L}*0.01571L=0.01393molPb(NO_3)_2

Next, since there is a 1:2 mole ratio between lead (II) nitrate and iodide ions, we compute the moles of those ions:

n_{I^-}=0.01393molPb(NO_3)_2*\frac{2molI^-}{1molPb(NO_3)_2} =0.02785molI^-

Finally, since the mixing of the two solutions produce a final volume of 40.71 mL (0.04071 L), the resulting concentration (molarity) of the iodide ions in the student's unknown turns out:

M_{I^-}=\frac{0.02785molI^-}{0.04071L}\\\\ M_{I^-}=0.6841M

Best regards!

5 0
3 years ago
Which law is used to determined the relationship between the volume and the number of moles
alukav5142 [94]

Answer:

Avogadro's Law

Explanation:

Avogadro's number (6.23 x 10^23)

Avogadro's law states that the volume and number of moles are proportional if pressure and temp remain constant.

8 0
4 years ago
Read 2 more answers
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