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ivolga24 [154]
3 years ago
14

How many grams of sodium nitrate will dissolve in 50 g of water at 20 degrees Celsius?

Chemistry
1 answer:
Vesna [10]3 years ago
4 0
The best method to solve how many grams of sodium nitrate that will be dissolve in water at 20 degrees Celsius is to use solubility table. Based on the solubility table, 88.3 g will dissolve in water in a 100g NaNO3. Therefore, get the percentage and multiply it to 50g. The answer is 44.15g
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On 100 corex
Julli [10]

Answer:

P(total) = 164 mmHg

Explanation:

Given data:

Partial pressure of helium = 77 mmHg

Partial pressure of nitrogen = 87 mmHg

Total pressure of flask = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P(He) + P(N₂)

P(total) =  77 mmHg + 87 mmHg

P(total) = 164 mmHg

3 0
2 years ago
A motorcycle traveling at 19 m/s starts to slow down steadily, then it stops completely in 10 seconds. What is the motorcycle ac
Dmitry [639]

Answer:

-1,9m/s^{2}

Explanatio:

a=\frac{v-v_{0} }{t}

=\frac{0-19}{10}=-1,9m/s^{2}

3 0
2 years ago
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.150 mol of HCl were
irinina [24]

Answer:

pH = 2.21

Explanation:

Hello there!

In this case, according to the reaction between NaF and HCl as the latter is added to the buffer:

NaF+HCl\rightarrow NaCl+HF

It is possible for us to see how more HF is formed as HCl is added and therefore, the capacity of this HF/NaF-buffer is diminished as it turns acid. Therefore, it turns out feasible for us to calculate the consumed moles of NaF and the produced moles of HF due to the change in moles induced by HCl:

n_{HF}^{new}=0.300mol+0.150mol=0.450mol\\\\n_{NaF}^{new}=0.200mol-0.150mol=0.050mol

Next, we calculate the resulting concentrations to further apply the Henderson-Hasselbach equation:

[HF]=\frac{0.450mol}{1.0L} =0.450M

[NaF]=\frac{0.050mol}{1.0L} =0.050M

Now, calculated the pKa of HF:

pKa=-log(6.8x10^{-4})=3.17

We can proceed to the HH equation:

pH=pKa+log(\frac{[NaF]}{[HF]} )\\\\pH=3.17+log(\frac{0.05M}{0.45M} )\\\\pH=2.21

Best regards!

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2 years ago
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3 years ago
What type of moon cycle do solar and lunar Eclipse occurs in
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Answer:

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