FIRST WE ...
subtract one value to the other to see how many valued we have in between
-7 - (-2) = 5
7-2=5
Both of the lines XY AND ZW have 5 units or points in between them.
Length = 5 units
They are congruent since XY = ZW in length and essentially are the same line but at different points
Yes
Example
1+1 = x
Hope this helps
(a brainliest would be appreciated)
Answer:
Option (4). Rhombus
Step-by-step explanation:
From the figure attached,
Distance AB = 
= 
= 
= 
Distance BC = 
= 
= 
Distance CD = 
= 
= 
Distance AD = 
= 
= 
Slope of AB (
) = 
= 
= 
Slope of BC (
) = 
= 
If AB and BC are perpendicular then,

But it's not true.
[
= -
]
It shows that the consecutive sides of the quadrilateral are not perpendicular.
Therefore, ABCD is neither square nor a rectangle.
Slope of diagonal BD =
= Not defined (parallel to y-axis)
Slope of diagonal AC =
= 0 [parallel to x-axis]
Therefore, both the diagonals AC and BD will be perpendicular.
And the quadrilateral formed by the given points will be a rhombus.
Here's your answer it's completely right