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3 years ago

Angle Pairs Relationships HW

Mathematics

1 answer:

WITCHER [35]3 years ago

7 0

Answer:

Step-by-step explanation:

1. A = 68

B = 112

c = 68

2. A = 127

3. A = 70

B = 55

C = 25

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An industrial model builder need several pieces of wire that are 7 3/8 inches long. How many whole pieces of wire of this length

serg [7]

Answer: 13 whole pieces of wire can be cut from that spool and $4.125\ inches$ of wire is left over.

Step-by-step explanation:

Convert from mixed number to improper fraction. To do it you must multiply the whole numbe part by the denominator of the fraction and then add the product to the numerator. The denominator does not change. Then:

$7\frac{3}{8}in=\frac{(7*8)+3}{8}in=\frac{59}{8}in$

Since the spool contains 100 inches of wire, you must divide this lenght by $\frac{59}{8}in$ :

$\frac{100in}{\frac{59}{8}in}=\frac{800}{59}$

Convert from improper fraction to mixed number:

- When you divide the numerator 800 by the denominator 59, the quotient is 13 (this is the whole number part)

- The remainder is 33 (This is the numerator of the fraction).

- The denominator does not change.

Then:

$13\frac{33}{59}$

Therefore 13 whole pieces can be cut from that spool.

The amount of wire left over is:

$100in-(\frac{59}{8}in)(13)=4.125in$

7 0

3 years ago

At a certain game at a school carnival, people won 42 small prizes and 18 large prizes. For every _____ small prizes won, there

yanalaym [24]

Answer:

For every 7 small prizes won, there were 3 large prizes won.

ratio : 42:18 or 7:3

3 0

3 years ago

What is the solution (a, c) to this system of linear equations?

weeeeeb [17]

This is how you do it :) let me know if you have any questions. Hope this helps :)

4 0

4 years ago

Read 2 more answers

Suppose Brianna decided that the error margin of her 95% confidence interval was too large and wanted an error margin of .05 whi

svetoff [14.1K]

Answer:

$n=\frac{0.26 (1-0.26)}{(\frac{0.05}{1.96})^2} =295.65 \approx =296$ (b)

Rounded up would be n =296

Step-by-step explanation:

Assuming this previous info: She randomly interested in the p selects 100 engineering majors, and 26 of them said they earned an A in Calc 1.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: