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Llana [10]
3 years ago
11

Write in decimal form 7+3/100+9/1000

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer:

7.039

Step-by-step explanation:

7 = 7

3/100 = .03

9/1000 = .009

therefore

7 + 3/100 + 9/1000 = 7 + .03 + .009

7.039

otez555 [7]3 years ago
3 0

Answer:

7.039

Step-by-step explanation:

7 + 3/100 + 9/1000

7 + 0.03 + 0.009

7.039

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Question 3 (Multiples and Factors] Three numbers are given below. Use prime factorisation to determine the HCF and LCM 1848 132
Ilia_Sergeevich [38]

Prime factorization involves rewriting numbers as products

The HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

<h3>How to determine the HCF</h3>

The numbers are given as: 1848, 132 and 462

Using prime factorization, the numbers can be rewritten as:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

The HCF is the product of the highest factors

So, the HCF is:

HCF = 2 * 3 * 11

HCF = 66

<h3>How to determine the LCM</h3>

In (a), we have:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

So, the LCM is:

LCM = 2^3 * 3 * 7 * 11

LCM  = 1848

Hence, the HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

Read more about prime factorization at:

brainly.com/question/9523814

4 0
2 years ago
Whats 69x420?????????
IRISSAK [1]

Answer:

28980

Step-by-step explanation:

Also "<em>nice</em>"

3 0
3 years ago
Find each rate and unit rate. A. 420 miles in 7 hours. B 360 customers in 30 days. C 40 meters in 16 sec. part d $7.96 for 5 pou
shtirl [24]

a. 60 miles/1 hour because 420/7

b. 12 customers/1 day because 360/30

c. 2.5 meters/1 sec because 40/16

d. $1.59/1 lb because  7.96/5


3 0
3 years ago
Read 2 more answers
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

8 0
3 years ago
The planner needs a clearance of 9 feet under the arch. Has the planner met the minimum height?
Assoli18 [71]

Answer:

Yes,planner has met the minimum height, as minimum height was 9 feet and maximum height of arc is 9.6 feet

Step-by-step explanation:

The question is incomplete as all the details have not been given in the question.I have attached the complete question and its options at the bottom. Consult in for better understanding.

As we can see that at the mid value, for x=4, the value of f(x)=9.4

It means that the maximum height occurs at mid of the arc where it is height is 9.6 feet above the ground.

It means that the planner has met the minimum height, as minimum height was 9 feet and maximum height of arc is 9.6 feet

4 0
4 years ago
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