The company has to study 199 machines.
In statistics, the standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean of the set, while a high standard deviation indicates that the values are spread out over a wider range.
It is given that;
Margin of error E = 0.7
Confidence interval 98% = 1-0.98 = 0.02
Standard deviation = 6 hours
Number of MRI machines needed per day n, = [(z alpha/2 * SD)/E]²
Z alpha/2 = 1.645 at alpha = 0.1
Inputting these values into n we have that
[(1.645*6)/0.7]²
= 14.1²
= 198.81 is approximately equal to 199
The company has to study 199 machines.
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Hello there!
Answer:
You can also round up to the nearest tenths is 15.1 to 15.0 and its going to be stay.
Step-by-step explanation:
First you had to switch sides of equation form.
Then you add by 0.3 from both sides of equation form.
And finally, simplify by equation. You can also cross out by -0.3+0.3 and it gave us equal to zero. Then you add 14.8+0.3 and it equal to 15.1. You had to used their variable and its should be the right answer.
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie
Answer:
Option 1 - Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation.
Step-by-step explanation:
Given : Process
Step 1: 4x + 2 = 10
Step 2: 4x = 8
To find : Which justification describes the process?
Solution :
From step 1 to step 2, we subtract 2 both sides
Step 1: 4x + 2 = 10
Subtracting 2 both side,
⇒ 4x + 2-2 = 10-2
Step 2: 4x = 8
So, The best justification is 'Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation'.
Therefore, Option 1 is correct.
8 printers for $145 each is a total of $1160.
3 laptops for $439 is a total of $1317.
Therefore, the price of 3 laptops for $439 each cost more than 8 printers for $145 each.
About 28cm
circumference of a circle =radius×3.14
3.14÷circumference of the circle (88cm)=28.04.
About 28cm.
