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Lina20 [59]
4 years ago
12

NEED HELP WITH

Mathematics
1 answer:
Fed [463]4 years ago
3 0
Let the average profit or loss in year 2006 be x millions, 


The average profit for the 8-year period, is the total sum of the profits (or losses) of each year, divided by 8:

so we have:

\displaystyle{ \frac{3.40+2.10+x+0.60+2.10+0.20+1.30+0.75}{8}=1

\displaystyle{\frac{10.45+x}{8}=1

10.45+x=8

x=8-10.45=-2.45


Answer: the loss in 2006, was 2.45 million dollars

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Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0
jeyben [28]
Didn't you mean "Find the possible value or values of z?  y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2).  Thus, the given equation has two equal, real solutions:  z=2 and z=-2.
5 0
3 years ago
I need these 2 questions answered fast please.​
shtirl [24]

Answer:

75 ft / none of these (43)

Step-by-step explanation:

formula: (area =1/2bh)

so you take base × height and then take half of that number (divide by 2)

5 0
3 years ago
Show all work please
gayaneshka [121]
Angles D and F are supplementary, so
.. (19x -26) +(7x -2) = 180
.. 26x = 208
.. x = 208/26 = 8

∠EFG = (7x -2)° = (7*8 -2)° = 54°

Selection C is appropriate.
7 0
3 years ago
FAST!! Evaluate tan60/cos45<br> √6<br> √3/2<br> √2/3<br> 1√6
evablogger [386]

Answer:

\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}

Step-by-step explanation:

We want to evaluate

\frac{\tan 60\degree}{\cos45 \degree}

We use special angles or the unit circle to obtain;

\frac{\tan 60\degree}{\cos45 \degree}=\frac{\sqrt{3}}{\frac{\sqrt{2}}{2}}

This implies that;

\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\div \frac{\sqrt{2}}{2}

\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\times \sqrt{2}

\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}

4 0
3 years ago
Read 2 more answers
EASY points here Solve for H; P=2L+2H
e-lub [12.9K]
P=2L+2H
First, isolate 2H:
2H=P-2L
Second, get a singular value of H (just H):
2H/2=(P-2L)/2

Final answer: 

H=\frac{P-2L}{2}
7 0
3 years ago
Read 2 more answers
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