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Nonamiya [84]
2 years ago
9

Find two numbers that have a sum of 13 and a product of -14

Mathematics
2 answers:
san4es73 [151]2 years ago
5 0

Answer:

7

Step-by-step explanation:

Because 6+7= 13 and 7 times -7 = -14

Make sure you go vote for my teacher link:  

brainly.com/educator/nomination/adam-ericson/  

garik1379 [7]2 years ago
3 0

Answer:

14 and -1

Step-by-step explanation:

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How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.
kifflom [539]
<h2><u>QUADRATIC EQUATION</u></h2>

<h2>\mathbb{ANSWER:}</h2>
  • \bold{x = 0.8 \: } \:  \sf \:  {\color{grey}or} \:  \:  \:  \bold{ x=  \frac{4}{5} } \\

  • \bold{x =  - 6}

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

\bold{Given \:  Equation: \color{brown} 5x²+26x-24=0}

First, add 24 to both sides.

  • \bold{5x²+26x-24 - \purple{ 24} = 0 +  \purple{24}}

  • \bold{ \implies \: 5x²+26x = 24 }

Since the coefficient of 5x² is 5, divide both sides by 5.

  • \bold{ \frac{5 {x}^{2} + 26x }{5} =  \frac{24}{5}  } \\

  • \bold{ \implies \:  {x}^{2} +  \frac{26}{5} x =  \frac{24}{5}  } \\

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

  • \bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  \purple{169}}{ \purple{25}}=  \frac{24}{5}    +  \frac{ \purple{169}}{ \purple{25}} } \\

  • \bold{ \implies \:\bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  169}{ {25}}=  \frac{289}{25}  } } \\

Factor the left side.

  • \bold{(x +  \frac{13}{5} ) {}^{2} =  \frac{289}{25}  } \\

Take square root.

  • \bold{x +  \frac{13}{5} = ±  \:  \sqrt{ \frac{289}{25}  }} \\

Then, add (-13)/5 to both sides.

  • \bold{x +  \frac{13}{5} +  \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \:      \sqrt{ \frac{289}{25}}} \\

  • \bold{  \: x =  \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\

  • \implies \: \underline{ \boxed{ \bold{   \frac{4}{5}  } \sf  \:  \: or \:  \:  \bold{ x =  - 6}}} \\

_______________❖_______________

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First combine like terms.

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16+p=17

Subtract 16 from both sides of the equation.

16-16+p=17-16

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You can check to see if the solution is true by substituting 1 into the original equation.

7+1+9=17

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