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irinina [24]
3 years ago
8

How do I simplify this?

Mathematics
1 answer:
Talja [164]3 years ago
6 0
Break it down step by step. photo math will show you how to break it down and you will have your answer
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Brody bought 17 chicken wings for $37.40. What's the unit cost of one wing?
lana [24]

<u>2.2</u>

Question:

Brody bought 17 chicken wings for $37.40. What's the unit cost of one wing?

Solution given:

17 chicken wings = $37.40

1chicken wings =$37.40/17*1=$2.2

<u>2</u><u>.</u><u>2</u>

7 0
3 years ago
Pls pls help me please!!!!
BigorU [14]

Answer:

Move 6.2 units up

Step-by-step explanation:

(-5.4, 6.2)

The first coordinate is the x coordinate

Positive x moves to the right, negative x moves to the left

Move 5.4 units to the left

The second  coordinate is the y coordinate

Positive y moves to up, negative y moves down

Move 6.2 units up

4 0
4 years ago
Which of these is closest in size to 1?<br> 0.95<br> 1.05<br> 0.960<br> 1.040<br> 0.95
Artemon [7]

Answer:

0.960

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What’s the answer for this I need help
Rama09 [41]

Answer:

18 ft^2

Step-by-step explanation:

4 x 4 = 16

4 x 1 = 4

4 / 2 = 2

16 + 2 = 18 ft.^2

4 0
3 years ago
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Is the confidence interval affected by the fact that the data appear to be from a population that is not normally​ distributed?
sp2606 [1]

Answer:

D. No, because the sample size is large enough.

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the sample size is higher than 30, on this case the answer would be:

D. No, because the sample size is large enough.

And the reason is given by The Central Limit Theorem since states if the individual distribution is normal then the sampling distribution for the sample mean is also normal.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

If the sample size it's not large enough n<30, on that case the distribution would be not normal.

7 0
3 years ago
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