Answer:
1
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
2
+
5
−
2
=
0
x^{2}+5x-2=0
x2+5x−2=0
=
1
a={\color{#c92786}{1}}
a=1
=
5
b={\color{#e8710a}{5}}
b=5
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
5
±
5
2
−
4
⋅
1
(
−
2
)
√
2
⋅
1
Step-by-step explanation:
this should help
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Answer: Yes it is!
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
400÷25
=16
25×16
=400
Answer:
Step-by-step explanation:
we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e
- the area of the square equal to the area of the rectangle
therefore,
recall the formula of the area of square and rectangle so,
now assign variables
thus substitute:
simplify square:
divide both sides by 32:
and we're done!
