Bob has 8 slices of pizza and he gets 12.5 more he does this 9.5 times how many pizzas did he eat. This is all I could think of
Im pretty sure i can help you out on this one
Answer:
Step-by-step explanation:
21)
The sine rule is expressed as
a/SinA = b/SinB = c/SinC
Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Therefore,
12/Sin 64 = x/Sin 12
Cross multiplying, it becomes
xSin 64 = 12Sin12
xSin 64 = 12 × 0.209
0.8988x = 2.508
x = 2.508/0.8988
x = 2.79
The sum of the angles in a triangle is 180 degrees. Therefore, the unknown angle in triangle is
180 - (64 + 12) = 104 degrees. Therefore,
y/Sin104 = 12/Sin64
ySin64 = 12Sin104
0.8988y = 12 × 0.9703 = 11.6436
y = 11.6436/0.8988
y = 12.95
22) we would apply the law of Cosines which is expressed as
a² = b² + c² - 2bcCosA
Therefore,
28² = 20² + 24² - 2 × 20 × 24Cosx
784 = 400 + 576 - 960Cosx
784 = 976 - 960Cosx
960Cosx = 976 - 784 = 192
Cosx = 192/960 = 0.2
x = Cos^(-1)0.2
x = 78.5°
This may help you
he functión Cot[x/2] is not continuos in the points
<span>x=2nπ, where n=0,1,2,3,...</span>
You can check it with a calculator. So the function is not continuos in
the domain the problem gives you, so the Rolle's theorem can not be
applied. If the inteverval was,
<span>[π/2,3π/2]</span>
Then we could apply the Rolle's theorem.
In statistics, a Chi-squared test may be used to determine holiday choice and gender and α (alpha) is the response variable.
<h3>What is the Chi-squared test? </h3>
A statistical technique called the chi-square test is used to compare actual outcomes with predictions.
The goal of this test is to establish if a discrepancy between actual and predicted data is the result of chance or a correlation between the variables you are researching.
Whether there is a statistically significant association between categorical variables is determined by the Chi-square test of independence.
This issue is addressed by a hypothesis test. The chi-square test of association is another name for this assessment.
Hence,in stats would a test looking at gender & holiday preference yes you can do a Chi-squared test and α(alpha) is the response variable.
To learn more about the Chi-squared test refer;
brainly.com/question/14082240
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