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mafiozo [28]
3 years ago
13

Find the radius of the circle with equation x^2 + y^2 - 10x - 16y + 53 = 0.

Mathematics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

<h2>radius = 10.5 units</h2>

Step-by-step explanation:

Equation of a circle is given by

x² + y² + 2gx + 2fy + c = 0

To find the radius of the circle we use the formula

r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }

where g and f is the center of the circle

From the question

x² + y² - 10x - 16y + 53 = 0

Comparing with the general equation above we have

2g = - 10 2f = - 16

g = - 5 f = - 8

c = 53

Substitute the values into the above formula

That's

r =  \sqrt{ ({ - 10})^{2}  + ( { - 8})^{2} - 53 }

r =  \sqrt{100 + 64 - 53}

r =  \sqrt{111}

We have the final answer as

<h3>radius = 10.5 units</h3>

Hope this helps you

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3 0
3 years ago
Which rule is an example of rigid transformation?
GalinKa [24]

We know that

Rigid transformation:

A rigid transformation (also called an isometry) is a transformation of the plane that preserves length.

Reflections, translations, rotations, and combinations of these three transformations are "rigid transformations"

so, it's length must be preserved

now, we will check each option

option-A:

we have (x,3y)

y-value changes but x-value will remain same

It changes length

so, this is not rigid transformation

option-B:

we have (3x,y)

x-value changes but y-value will remain same

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so, this is not rigid transformation

option-C:

(2x, y+2)

It changes length of x-value

but it is only shifting y-value

so, it changes length

so, this is not rigid transformation

option-D:

Both shifts values

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6 0
3 years ago
Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
What is b?<br> − ( 3 − 6b ) = 6b + 5
zubka84 [21]

Answer:

-1 1/2

Step-by-step explanation:

-(3-6b)=6b + 5 .remember to balance!!!!

-6b + 6b= 6b + 6b

-3=12b+5

-3+5=5-5

-8=12b   now divide since its the inverse operation

think 12/-8= -1 1/2

so B equals - 1 1/2

3 0
3 years ago
(07.03 LC) The steps below show the incomplete solution to find the value of q for the equation 4q − 2q − 4 = −1 + 21: Step 1: 4
Elza [17]

Answer:

3: 2q − 4 = 20

Step-by-step explanation:

Solve for q:

2 q - 4 = 20

Add 4 to both sides:

2 q + (4 - 4) = 4 + 20

4 - 4 = 0:

2 q = 20 + 4

20 + 4 = 24:

2 q = 24

Divide both sides of 2 q = 24 by 2:

(2 q)/2 = 24/2

2/2 = 1:

q = 24/2

The gcd of 24 and 2 is 2, so 24/2 = (2×12)/(2×1) = 2/2×12 = 12:

Answer:  q = 12

8 0
3 years ago
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