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melisa1 [442]
3 years ago
6

If the mean of the following distribution is 91 and sum of frequencies is 150 find x and y

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0

Answer:

Step-by-step explanation:

Mean = ∑x/ N

91 = ∑x / 150

∑x = 150 * 91 = 13650

x= 6825 and y = 6825

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a father is 10 times as old as his son. in 5 years he will be 5 times as old as his son. how old is the father and the son now
inn [45]

Answer:

The father is 40 and the son is 4.

Step-by-step explanation:

40 + 5 = 45.

4 +5=9.

45 divided by 5 = 9

5 0
3 years ago
4x-3=5x-21 what does x=
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7 ^ 8 times 7 ^ 3 times 7 ^ 4 / 7 ^ 9 times 7 ^ 5​
Alex777 [14]

Answer:

7^8 =5764801 * 7^3 =343 * 7^4 =2401 ÷ 7^9 = 40353607 * 7^5 =16807

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4 0
3 years ago
The population of a town grows at a rate proportional to the population present at time t. The initial population of 500 increas
Mazyrski [523]

Answer:

The population in 40 years will be 1220.

Step-by-step explanation:

The population of a town grows at a rate proportional to the population present at time t.

This means that:

P(t) = P(0)e^{rt}

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The initial population of 500 increases by 25% in 10 years.

This means that P(0) = 500, P(10) = 1.25*500 = 625

We apply this to the equation and find t.

P(t) = P(0)e^{rt}

625 = 500e^{10r}

e^{10r} = \frac{625}{500}

e^{10r} = 1.25

Applying ln to both sides

\ln{e^{10r}} = \ln{1.25}

10r = \ln{1.25}

r = \frac{\ln{1.25}}{10}

r = 0.0223

So

P(t) = 500e^{0.0223t}

What will be the population in 40 years

This is P(40).

P(t) = 500e^{0.0223t}

P(40) = 500e^{0.0223*40} = 1220

The population in 40 years will be 1220.

7 0
3 years ago
A ___________ is used to change from one unit to another.
Marta_Voda [28]

Answer:

conversion factor

Step-by-step explanation:

that is what I found on the internet

hope it helps :)

6 0
3 years ago
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