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sergejj [24]
3 years ago
11

Lease help...

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0
Bank A = 1000 x  (1 + (0.04*6)) = $1,240

Bank B = 1000 x (1+0.03)^6 = $1,194.05

Bank A would be worth more

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

He should place it in Bank A

For bank A Total amount = $1240

For bank bA= $1196.68

Step-by-step explanation:

For bank A with simple interest rate of 4%

Interest = PRT/100

Interest =( 1000*4*6)/100

Interest=$240

Total amount = principal + interest

Total amount = $1000+$240

Total amount = $1240

For Bank B with compound interest rate of 3%

A = p(1+r/n)^(nt)

A = 1000(1+(0.03/6))^(6*6)

A = 1000*1.19668

A= $1196.68

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Simone saved $65.35 more than her brother Dan and $37.50 less than her sister Carly. Carly saved $127.75. Write and solve equati
elena55 [62]
Siamone has $65.32 + DAN 
Dan has CARLY - $37.50
CARLY = $127.75 
Plug Carly into Dan's equation... 
$127.75 - $37.50 = $90.20
DAN = $90.20
Plug Dan into Siamone's equation
$65.32 + $90.20 = $155.57
5 0
3 years ago
Read 2 more answers
For test Please Help!!!
jonny [76]

Answer:

x=24.621

Step-by-step explanation:

tan(72)=x/8

tan(72)×8=x

x=24.621

4 0
3 years ago
PLEASE HELP ME I AM DESPERATE
Paladinen [302]

Answer: B 5+5=10+4+4+4=12+3 10+12+3 25 lol

Step-by-step explanation:

5 0
3 years ago
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I have like five of these so I'm sorry.
myrzilka [38]

Answer:

z ≥ -5/6

Step-by-step explanation:

10z - 2 ≥ 4z - 7

6z ≥ -5

z ≥ -5/6

6 0
2 years ago
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Solve this system using matrices:
sweet [91]

Answer:

Step-by-step explanation:

A system of linear equations is one which may be written in the form

a11x1 + a12x2 + · · · + a1nxn = b1 (1)

a21x1 + a22x2 + · · · + a2nxn = b2 (2)

.

am1x1 + am2x2 + · · · + amnxn = bm (m)

Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the

xi

’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of

the form constant × x

Solving Linear Systems of Equations

We now introduce, by way of several examples, the systematic procedure for solving systems of linear

equations.

Here is a system of three equations in three unknowns.

x1+ x2 + x3 = 4 (1)

x1+ 2x2 + 3x3 = 9 (2)

2x1+ 3x2 + x3 = 7 (3)

We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1

in terms of x2 and x3

x1 = 4 − x2 − x3 (1’)

1

and substituting this solution into the remaining two equations

(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5

(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1

8 0
3 years ago
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