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sergejj [24]
3 years ago
11

Lease help...

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0
Bank A = 1000 x  (1 + (0.04*6)) = $1,240

Bank B = 1000 x (1+0.03)^6 = $1,194.05

Bank A would be worth more

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

He should place it in Bank A

For bank A Total amount = $1240

For bank bA= $1196.68

Step-by-step explanation:

For bank A with simple interest rate of 4%

Interest = PRT/100

Interest =( 1000*4*6)/100

Interest=$240

Total amount = principal + interest

Total amount = $1000+$240

Total amount = $1240

For Bank B with compound interest rate of 3%

A = p(1+r/n)^(nt)

A = 1000(1+(0.03/6))^(6*6)

A = 1000*1.19668

A= $1196.68

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Answer:

The answers are given in the attachment

Step-by-step explanation:

The detailed step by step calculations are shown in the attachment.

8 0
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Ok guys ik that this isn't a part of academic but i wanna say a story ... since i had 15 subs ive always wanted 100 .. like so b
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What inequality sign do you use if c is at most 3
lesya692 [45]
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You move left 4 units and right 3 units. You end at (-2, -1). Where did you start?
Evgesh-ka [11]

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6 0
3 years ago
How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98
Irina18 [472]

Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

8 0
3 years ago
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